# Generate all rotations of a given string

• Difficulty Level : Easy
• Last Updated : 11 Jul, 2022

Given a string S. The task is to print all the possible rotated strings of the given string.

Examples:

```Input : S = "geeks"
Output : geeks
eeksg
eksge
ksgee
sgeek

Input : S = "abc"
Output : abc
bca
cab```

Method 1 (Simple): The idea is to run a loop from i = 0 to n – 1 ( n = length of string) i.e for each point of rotation, copy the second part of the string in the temporary string and then copy the first part of the original string to the temporary string.

Below is implementation of the above approach:

## C++

 `// A simple C++ program to generate all rotations` `// of a given string` `#include` `using` `namespace` `std;`   `// Print all the rotated string.` `void` `printRotatedString(``char` `str[])` `{` `    ``int` `len = ``strlen``(str);`   `    ``// Generate all rotations one by one and print` `    ``char` `temp[len];` `    ``for` `(``int` `i = 0; i < len; i++)` `    ``{` `        ``int` `j = i;  ``// Current index in str` `        ``int` `k = 0;  ``// Current index in temp`   `        ``// Copying the second part from the point` `        ``// of rotation.` `        ``while` `(str[j] != ``'\0'``)` `        ``{` `            ``temp[k] = str[j];` `            ``k++;` `            ``j++;` `        ``}`   `        ``// Copying the first part from the point` `        ``// of rotation.` `        ``j = 0;` `        ``while` `(j < i)` `        ``{` `            ``temp[k] = str[j];` `            ``j++;` `            ``k++;` `        ``}`   `        ``printf``(``"%s\n"``, temp);` `    ``}` `}`   `// Driven Program` `int` `main()` `{` `    ``char` `str[] = ``"geeks"``;` `    ``printRotatedString(str);` `    ``return` `0;` `}`

## Java

 `// A simple Java program to generate all rotations` `// of a given string    `   `class` `Test` `{` `    ``// Print all the rotated string.` `    ``static` `void` `printRotatedString(String str)` `    ``{` `        ``int` `len = str.length();` `     `  `        ``// Generate all rotations one by one and print` `        ``StringBuffer sb; ` `        `  `        ``for` `(``int` `i = ``0``; i < len; i++)` `        ``{` `            ``sb = ``new` `StringBuffer();` `            `  `            ``int` `j = i;  ``// Current index in str` `            ``int` `k = ``0``;  ``// Current index in temp` `     `  `            ``// Copying the second part from the point` `            ``// of rotation.` `            ``for` `(``int` `k2 = j; k2 < str.length(); k2++) {` `                ``sb.insert(k, str.charAt(j));` `                ``k++;` `                ``j++;` `            ``}` `     `  `            ``// Copying the first part from the point` `            ``// of rotation.` `            ``j = ``0``;` `            ``while` `(j < i)` `            ``{` `                ``sb.insert(k, str.charAt(j));` `                ``j++;` `                ``k++;` `            ``}` `     `  `            ``System.out.println(sb);` `        ``}` `    ``}` `    `  `    ``// Driver method` `    ``public` `static` `void` `main(String[] args) ` `    ``{` `        ``String  str = ``new` `String(``"geeks"``);` `        ``printRotatedString(str);` `    ``}` `}`

## Python3

 `# A simple Python3 program to generate ` `# all rotations of a given string `   `# Print all the rotated strings. ` `def` `printRotatedString(``str``): `   `    ``lenn ``=` `len``(``str``) `   `    ``# Generate all rotations` `    ``# one by one and print` `    ``temp ``=` `[``0``] ``*` `(lenn)` `    ``for` `i ``in` `range``(lenn):     ` `        ``j ``=` `i ``# Current index in str ` `        ``k ``=` `0` `# Current index in temp `   `        ``# Copying the second part from ` `        ``# the point of rotation. ` `        ``while` `(j < ``len``(``str``)): ` `        `  `            ``temp[k] ``=` `str``[j] ` `            ``k ``+``=` `1` `            ``j ``+``=` `1` `        `    `        ``# Copying the first part from ` `        ``# the point of rotation. ` `        ``j ``=` `0` `        ``while` `(j < i) :` `        `  `            ``temp[k] ``=` `str``[j] ` `            ``j ``+``=` `1` `            ``k ``+``=` `1` `        `    `        ``print``(``*``temp, sep ``=` `"") ` `    `  `# Driver Code` `if` `__name__ ``=``=` `'__main__'``:` `    ``str` `=` `"geeks"` `    ``printRotatedString(``str``)` `    `  `# This code is contributed ` `# by SHUBHAMSINGH10`

## C#

 `// A simple C# program to generate ` `// all rotations of a given string     ` `using` `System;` `using` `System.Text;`   `class` `GFG` `{` `// Print all the rotated string. ` `public` `static` `void` `printRotatedString(``string` `str)` `{` `    ``int` `len = str.Length;`   `    ``// Generate all rotations one` `    ``// by one and print ` `    ``StringBuilder sb;`   `    ``for` `(``int` `i = 0; i < len; i++)` `    ``{` `        ``sb = ``new` `StringBuilder();`   `        ``int` `j = i; ``// Current index in str` `        ``int` `k = 0; ``// Current index in temp`   `        ``// Copying the second part from ` `        ``// the point of rotation. ` `        ``for` `(``int` `k2 = j; k2 < str.Length; k2++)` `        ``{` `            ``sb.Insert(k, str[j]);` `            ``k++;` `            ``j++;` `        ``}`   `        ``// Copying the first part from ` `        ``// the point of rotation. ` `        ``j = 0;` `        ``while` `(j < i)` `        ``{` `            ``sb.Insert(k, str[j]);` `            ``j++;` `            ``k++;` `        ``}`   `        ``Console.WriteLine(sb);` `    ``}` `}`   `// Driver Code ` `public` `static` `void` `Main(``string``[] args)` `{` `    ``string` `str = ``"geeks"``;` `    ``printRotatedString(str);` `}` `}`   `// This code is contributed ` `// by Shrikant13`

## PHP

 ``

## Javascript

 ``

Output

```geeks
eeksg
eksge
ksgee
sgeek```

Time complexity: O(n2) where n is length of string
Auxiliary Space: O(n)

Method 2 (Tricky and Efficient): The idea is based on the efficient method to check if strings are rotations of each other or not. We concatenate str with itself, i.e., we do str.str where . is concatenation operator. Now we traverse the concatenated string from 0 to n – 1 and print all substrings of size n.

Below is the implementation of above approach:

## C++

 `// An efficient C++ program to print all` `// rotations of a string.` `#include` `using` `namespace` `std;`   `// Print all the rotated string.` `void` `printRotatedString(``char` `str[])` `{` `    ``int` `n = ``strlen``(str);`   `    ``// Concatenate str with itself` `    ``char` `temp[2*n + 1];` `    ``strcpy``(temp, str);` `    ``strcat``(temp, str);`   `    ``// Print all substrings of size n.` `    ``// Note that size of temp is 2n` `    ``for` `(``int` `i = 0; i < n; i++)` `    ``{` `        ``for` `(``int` `j=0; j != n; j++)` `            ``printf``(``"%c"``,temp[i + j]);` `        ``printf``(``"\n"``);` `    ``}` `}`   `// Driven Program` `int` `main()` `{` `    ``char` `str[] = ``"geeks"``;` `    ``printRotatedString(str);` `    ``return` `0;` `}`

## Java

 `// A simple Java program to generate all rotations` `// of a given string    `   `class` `Test` `{` `    ``// Print all the rotated string.` `    ``static` `void` `printRotatedString(String str)` `    ``{` `        ``int` `n = str.length();` `      `  `        ``StringBuffer sb = ``new` `StringBuffer(str);` `        ``// Concatenate str with itself` `        ``sb.append(str);` `     `  `        ``// Print all substrings of size n.` `        ``// Note that size of sb is 2n` `        ``for` `(``int` `i = ``0``; i < n; i++)` `        ``{` `            ``for` `(``int` `j=``0``; j != n; j++)` `                ``System.out.print(sb.charAt(i + j));` `            ``System.out.println();` `        ``}` `    ``}` `    `  `    ``// Driver method` `    ``public` `static` `void` `main(String[] args) ` `    ``{` `        ``String  str = ``new` `String(``"geeks"``);` `        ``printRotatedString(str);` `    ``}` `}`

## Python3

 `# An efficient Python3 program to print  ` `# all rotations of a string. `   `# Print all the rotated string. ` `def` `printRotatedString(string) :` `    `  `    ``n ``=` `len``(string)`   `    ``# Concatenate str with itself ` `    ``temp ``=` `string ``+` `string`   `    ``# Print all substrings of size n. ` `    ``# Note that size of temp is 2n ` `    ``for` `i ``in` `range``(n) :` `        `  `        ``for` `j ``in` `range``(n) :` `            ``print``(temp[i ``+` `j], end ``=` `"")` `            `  `        ``print``() `   `# Driver Code` `if` `__name__ ``=``=` `"__main__"` `: `   `    ``string ``=` `"geeks"` `    ``printRotatedString(string)`   `# This code is contributed by Ryuga`

## C#

 `// A simple C# program to generate all rotations` `// of a given string ` `using` `System;` `using` `System.Text;`   `class` `Test` `{` `    `  `    ``// Print all the rotated string.` `    ``static` `void` `printRotatedString(String str)` `    ``{` `        ``int` `n = str.Length;` `    `  `        ``StringBuilder sb = ``new` `StringBuilder(str);` `        ``// Concatenate str with itself` `        ``sb.Append(str);` `    `  `        ``// Print all substrings of size n.` `        ``// Note that size of sb is 2n` `        ``for` `(``int` `i = 0; i < n; i++)` `        ``{` `            ``for` `(``int` `j=0; j != n; j++)` `                ``Console.Write(sb[i + j]);` `            ``Console.WriteLine();` `        ``}` `    ``}` `    `  `    ``// Driver method` `    ``public` `static` `void` `Main(String[] args) ` `    ``{` `        ``String str = ``"geeks"``;` `        ``printRotatedString(str);` `    ``}` `}`

## PHP

 ``

## Javascript

 ``

Output

```geeks
eeksg
eksge
ksgee
sgeek```

Time complexity: O(n2) where n is length of string
Auxiliary Space : O(n)

This article is contributed by Anuj Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks

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