GATE | Gate IT 2008 | Question 9
What Boolean function does the circuit below realize ?
Explanation: There 0, 2, 5, 7 are enable input in given decoder.
Therefore, given K-Map should be as following:
So, output of above K-Map is,
= xz + x'z' = (x⊙z) = x (ex-nor) z
But, there given gate is NOR instead of OR, therefore above output will be negatated.
So, output function f is,
f = (xz + x'z')' = x'z + xz' = (x⊕z) = x (xor) z
So, option (B) is correct.
This explanation is contributed by Deep Shah.
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