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# GATE | Gate IT 2007 | Question 59

• Last Updated : 14 Feb, 2018

In the waveform (a) given below, a bit stream is encoded by Manchester encoding scheme. The same bit stream is encoded in a different coding scheme in wave form (b). The bit stream and the coding scheme are

(A) 1000010111 and Differential Manchester respectively
(B) 0111101000 and Differential Manchester respectively
(C) 1000010111 and Integral Manchester respectively
(D) 0111101000 and Integral Manchester respectively

Explanation: In simple language, Manchester encoding has +A to -A transition for the clock cycle for which bit is ‘1’ and transition from -A to +A for the cycle when bit is ‘0’ (A is the amplitude).

The amplitudes are bipolar in Differential manchester encoding same as manchester encoding just that it toggles at ‘1’. When bit is ‘1’ we get transition from +A to -A and it remains the same until next ‘1’ arrives. The output changes to opposite transition (-A to +A) when next ‘1’ arrives.
The second encoding resembles the differential manchester code for the given number.

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This solution is contributed by Kriti Kushwaha.

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