GATE | GATE-IT-2004 | Question 45

A serial transmission Ti uses 8 information bits, 2 start bits, 1 stop bit and 1 parity bit for each character. A synchronous transmission T2 uses 3 eight bit sync characters followed by 30 eight bit information characters. If the bit rate is 1200 bits/second in both cases, what are the transfer rates of Ti and T2?
(A) 100 characters/sec, 153 characters/sec
(B) 80 characters/sec, 136 characters/sec
(C) 100 characters/sec, 136 characters/sec
(D) 80 characters/sec, 153 characters/sec


Answer: (C)

Explanation:
Serial communication :

Total number of bits transmitted = 8 + 2 + 1 + 1 = 12 bits
Bit rate = 1200 / second
Transfer Rate = 1200 * (8/12) = 800 bits/sec = 100 bytes/sec = 100 characters/sec

Synchronous transmission :

Total number of bits transmitted = 3 + 30 = 33 bits
Transfer Rate = 1200 * (30/33) = 1090.90 bits/sec
Given size of one character is 8 bits.
So, Transfer Rate = 1090.90 bits/sec = 1090/8 = 136 characters/sec.

So,


Thus, option (C) is correct.


Please comment below if you find anything wrong in the above post.


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