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GATE | GATE-CS-2015 (Set 2) | Question 17

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  • Last Updated : 29 Sep, 2021
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The minimum number of JK flip-flops required to construct a synchronous counter with the count sequence (0, 0, 1, 1, 2, 2, 3, 3, 0, 0,…) is ________
(A) 0
(B) 1
(C) 2
(D) 3


Answer: (D)

Explanation: Count sequence they are saying is :
00, 00, 01, 01, 10, 10, 11, 11
We can see repeated sequence above. So two bits will not be sufficient, we need atleast three flip flops.
So, answer is 3.



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