GATE | GATE CS 2013 | Question 55
Consider the FDs given in above question. The relation R is
(A) in 1NF, but not in 2NF.
(B) in 2NF, but not in 3NF.
(C) in 3NF, but not in BCNF.
(D) in BCNF
Explanation: The table is not in 2nd Normal Form as the non-prime attributes are dependent on subsets of candidate keys.
The candidate keys are AD, BD, ED and FD. In all of the following FDs, the non-prime attributes are dependent on a partial candidate key.
A -> BC
B -> CFH
F -> EG
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