GATE | GATE-CS-2006 | Question 27
Consider the following propositional statements:
P1 : ((A ∧ B) → C)) ≡ ((A → C) ∧ (B → C))
P2 : ((A ∨ B) → C)) ≡ ((A → C) ∨ (B → C))
Which one of the following is true?
(A) P1 is a tautology, but not P2
(B) P2 is a tautology, but not P1
(C) P1 and P2 are both tautologies
(D) Both P1 and P2 are not tautologies
Explanation: The easiest way to solve this question by creating truth tables for the expressions given. Note that P1 will be a tautology if truth table for left expression is exactly same as truth table for right expression. Same holds for P2 also.
|A||B||C||((A ∧ B) → C))||((A → C) ∧ (B → C))||((A ∨ B) → C))||((A → C) ∨ (B → C))|
So as we see from table, none of the P1 or P2 are tautologies, so option (D) is correct.