GATE | GATE-CS-2005 | Question 51
Box P has 2 red balls and 3 blue balls and box Q has 3 red balls and 1 blue ball. A ball is selected as follows:
(i) Select a box (ii) Choose a ball from the selected box such that each ball in the box is equally likely to be chosen. The probabilities of selecting boxes P and Q are (1/3) and (2/3), respectively.
Given that a ball selected in the above process is a red ball, the probability that it came from the box P is
The probability of selecting a red ball = (1/3) * (2/5) + (2/3) * (3/4) = 2/15 + 1/2 = 19/30 [Let it be P1] Probability of selecting a red ball from box P = (1/3) * (2/5) = 2/15 [Let it be P2] Given that a ball selected in the above process is a red ball, the probability that it came from the box P is = P1/P2 = (2/15) / (19/30) = 4/19