GATE CS 2018
Their, they're, there
They're, their, there
There, their, they're
What is the area of the circle which has the diagonal of the square as its diameter if the area of square is ' d ' ?
One important observation to solve
the question :
Diagonal of Square = Diameter of Circle.
Let side of square be x.
From Pythagoras theorem.
Diagonal = √(2*x*x)
We know area of square = x * x = d
Diameter = Diagonal = √(2*d)
Radius = √(d/2)
Area of circle = π * √(d/2) * √(d/2) = 1/2 * π * d
∠ BCD - ∠ BAD
∠ BAD + ∠ BCF
∠ BAD + ∠ BCD
∠ CBA + ∠ ADC
Let total males and females be 60x and 40x respectively. Total number of people = (60x + 40x) Total number of people who attended : 0.8(60x + 40x) = 80x Let y males attended. It is given all 1females attended 40x + y = 80x y = 40x which is same as females.Alternative Approach - Lets total number of people = 100. Therefore, 60 are male and and 40 are female. But total 80 guests are attended and all 40 female attended the party. So, there remaining (80 - 40 = 40) attendees should be male. Then the ration of male to female among attendees is 40 : 40 = 1 : 1
Three green faces and four red faces.
Four green faces and three red faces.
Five green faces and two red faces.
Six green faces and one red face
If pqr ≠ 0 and p^(-x) = 1/q, q^(-y) = 1/r, r^(-z) = 1/p, find the value of the product xyz ?
1 / pqr
Taking logs of given three values, we get
1/q = p-x -------(1) 1/r = q-y -------(2) 1/p = r-z -------(3) 1/q = p-x = r-xz [Putting value of p from (3)] = q-xyz [Putting value of r from (2)] = 1 / qxyz On comparing power of q both sides, we get xyz = 1
So, option (C) is correct.
In appreciative of social improvement completed in a town, a wealthy philanthropist decided to give gift of Rs. 750 to each male senior citizen and Rs. 1000 for female senior citizens. There are total 300 citizens and the 8/9th of total men and 2/3rd of total women claimed the gift. What is amount of money philanthropist paid?
Let there be x total men. Total amount paid = x * 750 * 8/9 + (300 - x)*1000*2/3 = x*2000/3 + 300*1000*2/3 - x*2000/3 = 200000