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# Flood Fill Algorithm

• Difficulty Level : Medium
• Last Updated : 18 Feb, 2023

Given a 2D screen arr[][] where each arr[i][j] is an integer representing the color of that pixel, also given the location of a pixel (X, Y) and a color C, the task is to replace the color of the given pixel and all the adjacent same-colored pixels with the given color.

Example:

Input: arr[][] = {
{1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 0, 0},
{1, 0, 0, 1, 1, 0, 1, 1},
{1, 2, 2, 2, 2, 0, 1, 0},
{1, 1, 1, 2, 2, 0, 1, 0},
{1, 1, 1, 2, 2, 2, 2, 0},
{1, 1, 1, 1, 1, 2, 1, 1},
{1, 1, 1, 1, 1, 2, 2, 1}}
X = 4, Y = 4, C = 3
Output:
1 1 1 1 1 1 1 1
1 1 1 1 1 1 0 0
1 0 0 1 1 0 1 1
1 3 3 3 3 0 1 0
1 1 1 3 3 0 1 0
1 1 1 3 3 3 3
1 1 1 1 1 3 1 1
1 1 1 1 1 3 3
Explanation:
The values in the given 2D screen indicate colors of the pixels. X and Y are coordinates of the brush, C is the color that should replace the previous color on screen[X][Y] and all surrounding pixels with the same color. Hence all the 2 are replaced with 3.

BFS Approach: The idea is to use BFS traversal to replace the color with the new color.

• Create an empty queue lets say Q.
• Push the starting location of the pixel as given in the input and apply replacement color to it.
• Iterate until Q is not empty and pop the front node (pixel position).
• Check the pixels adjacent to the current pixel and push into the queue if valid (had not been colored with replacement color and have the same color as the old color).

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach` `#include ` `using` `namespace` `std;`   `// Function that returns true if` `// the given pixel is valid` `bool` `isValid(``int` `screen[][8], ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `{` `    ``if``(x < 0 || x >= m || y < 0 || y >= n || screen[x][y] != prevC` `       ``|| screen[x][y]== newC)` `        ``return` `false``;` `    ``return` `true``;` `}`     `// FloodFill function` `void` `floodFill(``int` `screen[][8], ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `{` `    ``vector> queue;`   `    ``// Append the position of starting` `    ``// pixel of the component` `    ``pair<``int``,``int``> p(x,y);` `    ``queue.push_back(p);`   `    ``// Color the pixel with the new color` `    ``screen[x][y] = newC;`   `    ``// While the queue is not empty i.e. the` `    ``// whole component having prevC color` `    ``// is not colored with newC color` `    ``while``(queue.size() > 0)` `    ``{` `        ``// Dequeue the front node` `        ``pair<``int``,``int``> currPixel = queue[queue.size() - 1];` `        ``queue.pop_back();`   `        ``int` `posX = currPixel.first;` `        ``int` `posY = currPixel.second;`   `        ``// Check if the adjacent` `        ``// pixels are valid` `        ``if``(isValid(screen, m, n, posX + 1, posY, prevC, newC))` `        ``{` `            ``// Color with newC` `            ``// if valid and enqueue` `            ``screen[posX + 1][posY] = newC;` `            ``p.first = posX + 1;` `            ``p.second = posY;` `            ``queue.push_back(p);` `        ``}`   `        ``if``(isValid(screen, m, n, posX-1, posY, prevC, newC))` `        ``{` `            ``screen[posX-1][posY]= newC;` `            ``p.first = posX-1;` `            ``p.second = posY;` `            ``queue.push_back(p);` `        ``}`   `        ``if``(isValid(screen, m, n, posX, posY + 1, prevC, newC))` `        ``{` `            ``screen[posX][posY + 1]= newC;` `            ``p.first = posX;` `            ``p.second = posY + 1;` `            ``queue.push_back(p);` `        ``}`   `        ``if``(isValid(screen, m, n, posX, posY-1, prevC, newC))` `        ``{` `            ``screen[posX][posY-1]= newC;` `            ``p.first = posX;` `            ``p.second = posY-1;` `            ``queue.push_back(p);` `        ``}` `    ``}` `}` `    `  `int` `main()` `{` `    ``int` `screen[][8] ={` `    ``{1, 1, 1, 1, 1, 1, 1, 1},` `    ``{1, 1, 1, 1, 1, 1, 0, 0},` `    ``{1, 0, 0, 1, 1, 0, 1, 1},` `    ``{1, 2, 2, 2, 2, 0, 1, 0},` `    ``{1, 1, 1, 2, 2, 0, 1, 0},` `    ``{1, 1, 1, 2, 2, 2, 2, 0},` `    ``{1, 1, 1, 1, 1, 2, 1, 1},` `    ``{1, 1, 1, 1, 1, 2, 2, 1}};` `   `  `    ``// Row of the display` `    ``int` `m = 8;` `   `  `    ``// Column of the display` `    ``int` `n = 8;` `   `  `    ``// Co-ordinate provided by the user` `    ``int` `x = 4;` `    ``int` `y = 4;` `   `  `    ``// Current color at that co-ordinate` `    ``int` `prevC = screen[x][y];` `   `  `    ``// New color that has to be filled` `    ``int` `newC = 3;` `    ``floodFill(screen, m, n, x, y, prevC, newC);` `   `  `    ``// Printing the updated screen` `    ``for``(``int` `i = 0; i < m; i++)` `    ``{` `        ``for``(``int` `j = 0; j < n; j++)` `        ``{` `            ``cout << screen[i][j] << ``" "``;` `        ``}` `        ``cout << endl;` `    ``}`   `    ``return` `0;` `}`   `// This code is contributed by suresh07.`

## Java

 `// Java implementation of the approach` `import` `java.util.*;` `import` `java.awt.Point;` `public` `class` `Main` `{` `    ``// Function that returns true if` `    ``// the given pixel is valid` `    ``static` `boolean` `isValid(``int``[][] screen, ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `    ``{` `        ``if``(x < ``0` `|| x >= m || y < ``0` `|| y >= n || screen[x][y] != prevC` `           ``|| screen[x][y]== newC)` `            ``return` `false``;` `        ``return` `true``;` `    ``}` `  `  `  `  `    ``// FloodFill function` `    ``static` `void` `floodFill(``int``[][] screen, ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `    ``{` `        ``Vector queue = ``new` `Vector();` `  `  `        ``// Append the position of starting` `        ``// pixel of the component` `        ``queue.add(``new` `Point(x, y));` `  `  `        ``// Color the pixel with the new color` `        ``screen[x][y] = newC;` `  `  `        ``// While the queue is not empty i.e. the` `        ``// whole component having prevC color` `        ``// is not colored with newC color` `        ``while``(queue.size() > ``0``)` `        ``{` `            ``// Dequeue the front node` `            ``Point currPixel = queue.get(queue.size() - ``1``);` `            ``queue.remove(queue.size() - ``1``);` `  `  `            ``int` `posX = currPixel.x;` `            ``int` `posY = currPixel.y;` `  `  `            ``// Check if the adjacent` `            ``// pixels are valid` `            ``if``(isValid(screen, m, n, posX + ``1``, posY, prevC, newC))` `            ``{` `                ``// Color with newC` `                ``// if valid and enqueue` `                ``screen[posX + ``1``][posY] = newC;` `                ``queue.add(``new` `Point(posX + ``1``, posY));` `            ``}` `  `  `            ``if``(isValid(screen, m, n, posX-``1``, posY, prevC, newC))` `            ``{` `                ``screen[posX-``1``][posY]= newC;` `                ``queue.add(``new` `Point(posX-``1``, posY));` `            ``}` `  `  `            ``if``(isValid(screen, m, n, posX, posY + ``1``, prevC, newC))` `            ``{` `                ``screen[posX][posY + ``1``]= newC;` `                ``queue.add(``new` `Point(posX, posY + ``1``));` `            ``}` `  `  `            ``if``(isValid(screen, m, n, posX, posY-``1``, prevC, newC))` `            ``{` `                ``screen[posX][posY-``1``]= newC;` `                ``queue.add(``new` `Point(posX, posY-``1``));` `            ``}` `        ``}` `    ``}` `    `  `    ``public` `static` `void` `main(String[] args) {` `        ``int``[][] screen ={` `        ``{``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``},` `        ``{``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``0``, ``0``},` `        ``{``1``, ``0``, ``0``, ``1``, ``1``, ``0``, ``1``, ``1``},` `        ``{``1``, ``2``, ``2``, ``2``, ``2``, ``0``, ``1``, ``0``},` `        ``{``1``, ``1``, ``1``, ``2``, ``2``, ``0``, ``1``, ``0``},` `        ``{``1``, ``1``, ``1``, ``2``, ``2``, ``2``, ``2``, ``0``},` `        ``{``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``1``, ``1``},` `        ``{``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``2``, ``1``}};` `      `  `        ``// Row of the display` `        ``int` `m = screen.length;` `      `  `        ``// Column of the display` `        ``int` `n = screen.length;` `      `  `        ``// Co-ordinate provided by the user` `        ``int` `x = ``4``;` `        ``int` `y = ``4``;` `      `  `        ``// Current color at that co-ordinate` `        ``int` `prevC = screen[x][y];` `      `  `        ``// New color that has to be filled` `        ``int` `newC = ``3``;` `        ``floodFill(screen, m, n, x, y, prevC, newC);` `      `  `        ``// Printing the updated screen` `        ``for``(``int` `i = ``0``; i < m; i++)` `        ``{` `            ``for``(``int` `j = ``0``; j < n; j++)` `            ``{` `                ``System.out.print(screen[i][j] + ``" "``);` `            ``}` `            ``System.out.println();` `        ``}` `    ``}` `}`   `// This code is contributed by mukesh07.`

## Python3

 `# Python3 implementation of the approach`   `# Function that returns true if ` `# the given pixel is valid` `def` `isValid(screen, m, n, x, y, prevC, newC):` `    ``if` `x<``0` `or` `x>``=` `m\` `       ``or` `y<``0` `or` `y>``=` `n ``or``\` `       ``screen[x][y]!``=` `prevC\` `       ``or` `screen[x][y]``=``=` `newC:` `        ``return` `False` `    ``return` `True`     `# FloodFill function` `def` `floodFill(screen,  ` `            ``m, n, x,  ` `            ``y, prevC, newC):` `    ``queue ``=` `[]` `    `  `    ``# Append the position of starting ` `    ``# pixel of the component` `    ``queue.append([x, y])`   `    ``# Color the pixel with the new color` `    ``screen[x][y] ``=` `newC`   `    ``# While the queue is not empty i.e. the ` `    ``# whole component having prevC color ` `    ``# is not colored with newC color` `    ``while` `queue:` `        `  `        ``# Dequeue the front node` `        ``currPixel ``=` `queue.pop()` `        `  `        ``posX ``=` `currPixel[``0``]` `        ``posY ``=` `currPixel[``1``]` `        `  `        ``# Check if the adjacent` `        ``# pixels are valid` `        ``if` `isValid(screen, m, n,  ` `                ``posX ``+` `1``, posY,  ` `                        ``prevC, newC):` `            `  `            ``# Color with newC` `            ``# if valid and enqueue` `            ``screen[posX ``+` `1``][posY] ``=` `newC` `            ``queue.append([posX ``+` `1``, posY])` `        `  `        ``if` `isValid(screen, m, n,  ` `                    ``posX``-``1``, posY,  ` `                        ``prevC, newC):` `            ``screen[posX``-``1``][posY]``=` `newC` `            ``queue.append([posX``-``1``, posY])` `        `  `        ``if` `isValid(screen, m, n,  ` `                ``posX, posY ``+` `1``,  ` `                        ``prevC, newC):` `            ``screen[posX][posY ``+` `1``]``=` `newC` `            ``queue.append([posX, posY ``+` `1``])` `        `  `        ``if` `isValid(screen, m, n,  ` `                    ``posX, posY``-``1``,  ` `                        ``prevC, newC):` `            ``screen[posX][posY``-``1``]``=` `newC` `            ``queue.append([posX, posY``-``1``])`       `# Driver code` `screen ``=``[` `[``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``], ` `[``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``0``, ``0``], ` `[``1``, ``0``, ``0``, ``1``, ``1``, ``0``, ``1``, ``1``], ` `[``1``, ``2``, ``2``, ``2``, ``2``, ``0``, ``1``, ``0``], ` `[``1``, ``1``, ``1``, ``2``, ``2``, ``0``, ``1``, ``0``], ` `[``1``, ``1``, ``1``, ``2``, ``2``, ``2``, ``2``, ``0``], ` `[``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``1``, ``1``], ` `[``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``2``, ``1``], ` `    ``]` `    `  `# Row of the display` `m ``=` `len``(screen)`   `# Column of the display` `n ``=` `len``(screen[``0``])`   `# Co-ordinate provided by the user` `x ``=` `4` `y ``=` `4`   `# Current color at that co-ordinate` `prevC ``=` `screen[x][y]`   `# New color that has to be filled` `newC ``=` `3`   `floodFill(screen, m, n, x, y, prevC, newC)`     `# Printing the updated screen` `for` `i ``in` `range``(m):` `    ``for` `j ``in` `range``(n):` `        ``print``(screen[i][j], end ``=``' '``)` `    ``print``()`

## C#

 `// C# implementation of the approach` `using` `System;` `using` `System.Collections.Generic;` `class` `GFG {` `    `  `    ``// Function that returns true if` `    ``// the given pixel is valid` `    ``static` `bool` `isValid(``int``[,] screen, ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `    ``{` `        ``if``(x < 0 || x >= m || y < 0 || y >= n || screen[x, y] != prevC` `           ``|| screen[x,y]== newC)` `            ``return` `false``;` `        ``return` `true``;` `    ``}` ` `  ` `  `    ``// FloodFill function` `    ``static` `void` `floodFill(``int``[,] screen, ``int` `m, ``int` `n, ``int` `x, ``int` `y, ``int` `prevC, ``int` `newC)` `    ``{` `        ``List> queue = ``new` `List>();` ` `  `        ``// Append the position of starting` `        ``// pixel of the component` `        ``queue.Add(``new` `Tuple<``int``,``int``>(x, y));` ` `  `        ``// Color the pixel with the new color` `        ``screen[x,y] = newC;` ` `  `        ``// While the queue is not empty i.e. the` `        ``// whole component having prevC color` `        ``// is not colored with newC color` `        ``while``(queue.Count > 0)` `        ``{` `            ``// Dequeue the front node` `            ``Tuple<``int``,``int``> currPixel = queue[queue.Count - 1];` `            ``queue.RemoveAt(queue.Count - 1);` ` `  `            ``int` `posX = currPixel.Item1;` `            ``int` `posY = currPixel.Item2;` ` `  `            ``// Check if the adjacent` `            ``// pixels are valid` `            ``if``(isValid(screen, m, n, posX + 1, posY, prevC, newC))` `            ``{` `                ``// Color with newC` `                ``// if valid and enqueue` `                ``screen[posX + 1,posY] = newC;` `                ``queue.Add(``new` `Tuple<``int``,``int``>(posX + 1, posY));` `            ``}` ` `  `            ``if``(isValid(screen, m, n, posX-1, posY, prevC, newC))` `            ``{` `                ``screen[posX-1,posY]= newC;` `                ``queue.Add(``new` `Tuple<``int``,``int``>(posX-1, posY));` `            ``}` ` `  `            ``if``(isValid(screen, m, n, posX, posY + 1, prevC, newC))` `            ``{` `                ``screen[posX,posY + 1]= newC;` `                ``queue.Add(``new` `Tuple<``int``,``int``>(posX, posY + 1));` `            ``}` ` `  `            ``if``(isValid(screen, m, n, posX, posY-1, prevC, newC))` `            ``{` `                ``screen[posX,posY-1]= newC;` `                ``queue.Add(``new` `Tuple<``int``,``int``>(posX, posY-1));` `            ``}` `        ``}` `    ``}` `    `  `  ``static` `void` `Main() {` `    ``int``[,] screen ={` `    ``{1, 1, 1, 1, 1, 1, 1, 1},` `    ``{1, 1, 1, 1, 1, 1, 0, 0},` `    ``{1, 0, 0, 1, 1, 0, 1, 1},` `    ``{1, 2, 2, 2, 2, 0, 1, 0},` `    ``{1, 1, 1, 2, 2, 0, 1, 0},` `    ``{1, 1, 1, 2, 2, 2, 2, 0},` `    ``{1, 1, 1, 1, 1, 2, 1, 1},` `    ``{1, 1, 1, 1, 1, 2, 2, 1}};` ` `  `    ``// Row of the display` `    ``int` `m = screen.GetLength(0);` ` `  `    ``// Column of the display` `    ``int` `n = screen.GetLength(1);` ` `  `    ``// Co-ordinate provided by the user` `    ``int` `x = 4;` `    ``int` `y = 4;` ` `  `    ``// Current color at that co-ordinate` `    ``int` `prevC = screen[x,y];` ` `  `    ``// New color that has to be filled` `    ``int` `newC = 3; ` `    ``floodFill(screen, m, n, x, y, prevC, newC);` ` `  `    ``// Printing the updated screen` `    ``for``(``int` `i = 0; i < m; i++)` `    ``{` `        ``for``(``int` `j = 0; j < n; j++)` `        ``{` `            ``Console.Write(screen[i,j] + ``" "``);` `        ``}` `        ``Console.WriteLine();` `    ``}` `  ``}` `}`   `// This code is contributed by divyeshrabadiya07.`

## Javascript

 ``

Output

```1 1 1 1 1 1 1 1
1 1 1 1 1 1 0 0
1 0 0 1 1 0 1 1
1 3 3 3 3 0 1 0
1 1 1 3 3 0 1 0
1 1 1 3 3 3 3 0
1 1 1 1 1 3 1 1
1 1 1 1 1 3 3 1 ```

Time Complexity: O(N*M)
Auxiliary Space: O(N*M)

An Approach using DFS:

• Change the color of source row and source column with given color
• Do dfs in four direction

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach` `#include ` `using` `namespace` `std;`   `// Floodfill function` `void` `floodFill(vector >& screen, ``int` `sr, ``int` `sc,` `               ``int` `row, ``int` `col, ``int` `source, ``int` `color)` `{` `    ``// Condition for checking out of bounds` `    ``if` `(sr < 0 || sr >= row || sc < 0 || sc >= col)` `        ``return``;`   `    ``if` `(screen[sr][sc] != source)` `        ``return``;` `  `  `    ``screen[sr][sc] = color;` `    ``floodFill(screen, sr - 1, sc, row, col, source,` `              ``color); ``// left` `    ``floodFill(screen, sr + 1, sc, row, col, source,` `              ``color); ``// right` `    ``floodFill(screen, sr, sc + 1, row, col, source,` `              ``color); ``// top` `    ``floodFill(screen, sr, sc - 1, row, col, source,` `              ``color); ``// bottom` `}`   `// Driver code` `int` `main()` `{` `    ``vector > screen` `        ``= { { 1, 1, 1, 1, 1, 1, 1, 1 },` `            ``{ 1, 1, 1, 1, 1, 1, 0, 0 },` `            ``{ 1, 0, 0, 1, 1, 0, 1, 1 },` `            ``{ 1, 2, 2, 2, 2, 0, 1, 0 },` `            ``{ 1, 1, 1, 2, 2, 0, 1, 0 },` `            ``{ 1, 1, 1, 2, 2, 2, 2, 0 },` `            ``{ 1, 1, 1, 1, 1, 2, 1, 1 },` `            ``{ 1, 1, 1, 1, 1, 2, 2, 1 } };`   `    ``// Row of the display` `    ``int` `m = 8;`   `    ``// Column of the display` `    ``int` `n = 8;`   `    ``// Co-ordinate provided by the user` `    ``int` `x = 4;` `    ``int` `y = 4;`   `    ``// Current color at that co-ordinate` `    ``int` `prevC = screen[x][y];`   `    ``// New color that has to be filled` `    ``int` `newC = 3;`   `    ``floodFill(screen, x, y, m, n, prevC, newC);`   `    ``// Printing the updated screen` `    ``for` `(``int` `i = 0; i < m; i++) {` `        ``for` `(``int` `j = 0; j < n; j++) {` `            ``cout << screen[i][j] << ``" "``;` `        ``}` `        ``cout << endl;` `    ``}`   `    ``return` `0;` `}`   `// This code is contributed by hkdass001.`

## Java

 `import` `java.util.ArrayList;`   `public` `class` `FloodFill {` `// Floodfill function` `public` `static` `void` `floodFill(``int``[][] screen, ``int` `sr, ``int` `sc,` `int` `row, ``int` `col, ``int` `source, ``int` `color) {` `// Condition for checking out of bounds` `if` `(sr < ``0` `|| sr >= row || sc < ``0` `|| sc >= col)` `return``;`   `    ``if` `(screen[sr][sc] != source)` `        ``return``;`   `    ``screen[sr][sc] = color;` `    ``floodFill(screen, sr - ``1``, sc, row, col, source, color); ``// left` `    ``floodFill(screen, sr + ``1``, sc, row, col, source, color); ``// right` `    ``floodFill(screen, sr, sc + ``1``, row, col, source, color); ``// top` `    ``floodFill(screen, sr, sc - ``1``, row, col, source, color); ``// bottom` `}`   `public` `static` `void` `main(String[] args) {` `    ``int``[][] screen = {{``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``},` `            ``{``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``0``, ``0``},` `            ``{``1``, ``0``, ``0``, ``1``, ``1``, ``0``, ``1``, ``1``},` `            ``{``1``, ``2``, ``2``, ``2``, ``2``, ``0``, ``1``, ``0``},` `            ``{``1``, ``1``, ``1``, ``2``, ``2``, ``0``, ``1``, ``0``},` `            ``{``1``, ``1``, ``1``, ``2``, ``2``, ``2``, ``2``, ``0``},` `            ``{``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``1``, ``1``},` `            ``{``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``2``, ``1``}};`   `    ``// Row of the display` `    ``int` `m = ``8``;`   `    ``// Column of the display` `    ``int` `n = ``8``;`   `    ``// Co-ordinate provided by the user` `    ``int` `x = ``4``;` `    ``int` `y = ``4``;`   `    ``// Current color at that co-ordinate` `    ``int` `prevC = screen[x][y];`   `    ``// New color that has to be filled` `    ``int` `newC = ``3``;`   `    ``floodFill(screen, x, y, m, n, prevC, newC);`   `    ``// Printing the updated screen` `    ``for` `(``int` `i = ``0``; i < m; i++) {` `        ``for` `(``int` `j = ``0``; j < n; j++) {` `            ``System.out.print(screen[i][j] + ``" "``);` `        ``}` `        ``System.out.println();` `    ``}` `}`   `}`

## Python3

 `from` `typing ``import` `List``, ``Tuple`   `def` `flood_fill(screen: ``List``[``List``[``int``]], sr: ``int``, sc: ``int``, row: ``int``, col: ``int``, source: ``int``, color: ``int``) ``-``> ``None``:` `    ``# Condition for checking out of bounds` `    ``if` `sr < ``0` `or` `sr >``=` `row ``or` `sc < ``0` `or` `sc >``=` `col:` `        ``return`   `    ``if` `screen[sr][sc] !``=` `source:` `        ``return`   `    ``screen[sr][sc] ``=` `color` `    ``flood_fill(screen, sr ``-` `1``, sc, row, col, source, color) ``# left` `    ``flood_fill(screen, sr ``+` `1``, sc, row, col, source, color) ``# right` `    ``flood_fill(screen, sr, sc ``+` `1``, row, col, source, color) ``# top` `    ``flood_fill(screen, sr, sc ``-` `1``, row, col, source, color) ``# bottom`   `if` `__name__ ``=``=` `"__main__"``:` `    ``screen ``=` `[` `        ``[``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``1``],` `        ``[``1``, ``1``, ``1``, ``1``, ``1``, ``1``, ``0``, ``0``],` `        ``[``1``, ``0``, ``0``, ``1``, ``1``, ``0``, ``1``, ``1``],` `        ``[``1``, ``2``, ``2``, ``2``, ``2``, ``0``, ``1``, ``0``],` `        ``[``1``, ``1``, ``1``, ``2``, ``2``, ``0``, ``1``, ``0``],` `        ``[``1``, ``1``, ``1``, ``2``, ``2``, ``2``, ``2``, ``0``],` `        ``[``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``1``, ``1``],` `        ``[``1``, ``1``, ``1``, ``1``, ``1``, ``2``, ``2``, ``1``]` `    ``]`   `    ``# Row of the display` `    ``m ``=` `8`   `    ``# Column of the display` `    ``n ``=` `8`   `    ``# Coordinate provided by the user` `    ``x ``=` `4` `    ``y ``=` `4`   `    ``# Current color at that coordinate` `    ``prevC ``=` `screen[x][y]`   `    ``# New color that has to be filled` `    ``newC ``=` `3`   `    ``flood_fill(screen, x, y, m, n, prevC, newC)`   `    ``# Printing the updated screen` `    ``for` `i ``in` `range``(m):` `        ``for` `j ``in` `range``(n):` `            ``print``(screen[i][j], end``=``" "``)` `        ``print``()`

## Javascript

 `// JavaScript implementation of the approach`     `// Floodfill function` `function` `floodFill(screen, sr, sc, row, col, source, color)` `{` `    ``// Condition for checking out of bounds` `    ``if` `(sr < 0 || sr >= row || sc < 0 || sc >= col) ``return``;`   `    ``if` `(screen[sr][sc] != source) ``return``;`   `    ``screen[sr][sc] = color;` `    ``floodFill(screen, sr - 1, sc, row, col, source, color); ``// left` `    ``floodFill(screen, sr + 1, sc, row, col, source, color); ``// right` `    ``floodFill(screen, sr, sc + 1, row, col, source, color); ``// top` `    ``floodFill(screen, sr, sc - 1, row, col, source, color); ``// bottom` `}`   `// Driver code` `let screen = [  [ 1, 1, 1, 1, 1, 1, 1, 1 ],` `                ``[ 1, 1, 1, 1, 1, 1, 0, 0 ],` `                ``[ 1, 0, 0, 1, 1, 0, 1, 1 ],` `                ``[ 1, 2, 2, 2, 2, 0, 1, 0 ],` `                ``[ 1, 1, 1, 2, 2, 0, 1, 0 ],` `                ``[ 1, 1, 1, 2, 2, 2, 2, 0 ],` `                ``[ 1, 1, 1, 1, 1, 2, 1, 1 ],` `                ``[ 1, 1, 1, 1, 1, 2, 2, 1 ] ];`     `// Row of the display` `let m = 8;`   `// Column of the display` `let n = 8;`   `// Co-ordinate provided by the user` `let x = 4;` `let y = 4;`   `// Current color at that co-ordinate` `let prevC = screen[x][y];`   `// New color that has to be filled` `let newC = 3;`   `floodFill(screen, x, y, m, n, prevC, newC);`   `// Printing the updated screen` `for` `(let i = 0; i < m; i++) {` `    ``let temp = ``""``;` `    ``for` `(let j = 0; j < n; j++) {` `           ``document.write(screen[i][j] + ``" "``);` `    ``}` `    ``document.write(``"
"``);` `}`     `// This code is contributed by Gautam goel`

## C#

 `using` `System;`   `namespace` `FloodFill` `{` `    ``class` `Program` `    ``{` `        ``static` `void` `Main(``string``[] args)` `        ``{` `            ``int``[,] screen =` `            ``{` `                ``{1, 1, 1, 1, 1, 1, 1, 1},` `                ``{1, 1, 1, 1, 1, 1, 0, 0},` `                ``{1, 0, 0, 1, 1, 0, 1, 1},` `                ``{1, 2, 2, 2, 2, 0, 1, 0},` `                ``{1, 1, 1, 2, 2, 0, 1, 0},` `                ``{1, 1, 1, 2, 2, 2, 2, 0},` `                ``{1, 1, 1, 1, 1, 2, 1, 1},` `                ``{1, 1, 1, 1, 1, 2, 2, 1}` `            ``};`   `            ``// Dimensions of the screen` `            ``int` `m = 8;` `            ``int` `n = 8;`   `            ``// Coordinates provided by the user` `            ``int` `x = 4;` `            ``int` `y = 4;`   `            ``// Current color at the given coordinate` `            ``int` `prevC = screen[x, y];`   `            ``// New color to fill` `            ``int` `newC = 3;`   `            ``FloodFill(screen, x, y, m, n, prevC, newC);`   `            ``// Printing the updated screen` `            ``for` `(``int` `i = 0; i < m; i++)` `            ``{` `                ``for` `(``int` `j = 0; j < n; j++)` `                ``{` `                    ``Console.Write(screen[i, j] + ``" "``);` `                ``}` `                ``Console.WriteLine();` `            ``}`   `            ``Console.ReadKey();` `        ``}`   `        ``// Flood fill function` `        ``static` `void` `FloodFill(``int``[,] screen, ``int` `sr, ``int` `sc, ``int` `row, ``int` `col, ``int` `source, ``int` `color)` `        ``{` `            ``// Check for out of bounds` `            ``if` `(sr < 0 || sr >= row || sc < 0 || sc >= col)` `                ``return``;`   `            ``// Check if the current pixel is not equal to the source color` `            ``if` `(screen[sr, sc] != source)` `                ``return``;`   `            ``screen[sr, sc] = color;`   `            ``// Recursively fill the surrounding pixels` `            ``FloodFill(screen, sr - 1, sc, row, col, source, color); ``// left` `            ``FloodFill(screen, sr + 1, sc, row, col, source, color); ``// right` `            ``FloodFill(screen, sr, sc + 1, row, col, source, color); ``// top` `            ``FloodFill(screen, sr, sc - 1, row, col, source, color); ``// bottom` `        ``}` `    ``}` `}`

Output

```1 1 1 1 1 1 1 1
1 1 1 1 1 1 0 0
1 0 0 1 1 0 1 1
1 3 3 3 3 0 1 0
1 1 1 3 3 0 1 0
1 1 1 3 3 3 3 0
1 1 1 1 1 3 1 1
1 1 1 1 1 3 3 1 ```

Time Complexity: O(m*n)
Auxiliary Space: O(m + n), due to the recursive call stack.

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