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# Find temperature of missing days using given sum and average

• Difficulty Level : Basic
• Last Updated : 01 Apr, 2021

Given integers x and y which denotes the average temperature of the week except for days Day1 and Day2 respectively, and the sum of the temperature of Day1 and Day2 as S, the task is to find the temperature of the days Day1 and Day2.
Examples:

Input: x = 15, y = 10, S = 50
Output: Day1 = 10, Day2 = 40
Explanation:
The average of week excluding Day1 is 15, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 50. Individual temperature of the two days are 10 and 40 respecticvely.
Input: x = 5, y = 10, s = 40
Output: Day1 = 35, Day2 = 5
Explanation:
The average of week excluding Day1 is 5, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 40. Individual temperature of the two days are 35 and 5 respecticvely.

Approach: We know that Average = sum of all observation / total number of observation. Hence, the sum of observation = Average * number of observation i.e., S = A * n

So after excluding Day1 or Day2 we are left with only 6 days
so N = 6 and the equations are:

and

on subtracting the above two equations we get,

(Equation 1)
and it is given in the problem statement that

(Equation 2)

Solving the above two equations, the value of Day1 and Day2 is given by:

[Tex]Day1 = S – Day2  [/Tex]

Below is the implementation of above approach:

## C++

 // C++ program for the above approach   #include  using namespace std;   // Function for finding the temperature void findTemperature(int x, int y, int s) {     double Day1, Day2;       // Store Day1 - Day2 in diff     double diff = (x - y) * 6;       Day2 = (diff + s) / 2;       // Remaining from s will be Day1     Day1 = s - Day2;       // Print Day1 and Day2     cout << "Day1 : " << Day1 << endl;     cout << "Day2 : " << Day2 << endl; }   // Driver Code int main() {     int x = 5, y = 10, s = 40;       // Functions     findTemperature(x, y, s);       return 0; }

## Java

 // Java program for the above approach class GFG{    // Function for finding the temperature static void findTemperature(int x, int y, int s) {     double Day1, Day2;        // Store Day1 - Day2 in diff     double diff = (x - y) * 6;        Day2 = (diff + s) / 2;        // Remaining from s will be Day1     Day1 = s - Day2;        // Print Day1 and Day2     System.out.println( "Day1 : " + Day1);     System.out.println( "Day2 : " + Day2); }    // Driver Code public static void main(String[] args) {     int x = 5, y = 10, s = 40;        // Functions     findTemperature(x, y, s); } }   // This code is contributed by rock_cool

## Python

 # Python3 program for the above approach   # Function for finding the temperature def findTemperature(x, y, s):       # Store Day1 - Day2 in diff     diff = (x - y) * 6     Day2 = (diff + s) // 2       # Remaining from s will be Day1     Day1 = s - Day2       # Print Day1 and Day2     print("Day1 : ", Day1)     print("Day2 : ", Day2)   # Driver Code if __name__ == '__main__':     x = 5     y = 10     s = 40       # Functions     findTemperature(x, y, s)   # This code is contributed by Mohit Kumar

## C#

 // C# program for the above approach using System; class GFG{     // Function for finding the temperature static void findTemperature(int x, int y, int s) {     double Day1, Day2;         // Store Day1 - Day2 in diff     double diff = (x - y) * 6;         Day2 = (diff + s) / 2;         // Remaining from s will be Day1     Day1 = s - Day2;         // Print Day1 and Day2     Console.Write( "Day1 : " + Day1 + '\n');     Console.WriteLine( "Day2 : " + Day2 + '\n'); }     // Driver Code public static void Main(string[] args) {     int x = 5, y = 10, s = 40;         // Functions     findTemperature(x, y, s); } }   // This code is contributed by Ritik Bansal

## Javascript

 

Output:

Day1 : 35
Day2 : 5

Time Complexity: O(1)
Auxiliary Space: O(1)

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