Fibonacci number in an array
We have been given an array and our task is to check if the element of array is present in Fibonacci series or not. If yes, then print that element.
Examples:
Input : 4, 2, 8, 5, 20, 1, 40, 13, 23 Output : 2 8 5 1 13 Here, Fibonacci series will be 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55. Numbers that are present in array are 2, 8, 5, 1, 13 For 2 -> 5 * 2 * 2 - 4 = 36 36 is a perfect square root of 6. Input : 4, 7, 6, 25 Output : No Fibonacci number in this array
A number is said to be in Fibonacci series if either (5 * n * n – 4) or (5 * n * n + 4) is a perfect square. Please refer check if a given number is Fibonacci number for details.
Implementation:
C++
// CPP program to find Fibonacci series numbers // in a given array. #include <bits/stdc++.h> using namespace std; // Function to check number is a // perfect square or not bool isPerfectSquare( int num) { int n = sqrt (num); return (n * n == num); } // Function to check if the number // is in Fibonacci or not void checkFib( int array[], int n) { int count = 0; for ( int i = 0; i < n; i++) { if (isPerfectSquare(5 * array[i] * array[i] + 4) || isPerfectSquare(5 * array[i] * array[i] - 4)) { cout << array[i] << " " ; count++; } } if (count == 0) cout << "None present" << endl; } // Driver function int main() { int array[] = { 4, 2, 8, 5, 20, 1, 40, 13, 23 }; int n = sizeof (array) / sizeof (array[0]); checkFib(array, n); return 0; } |
Java
// Java program to find Fibonacci series numbers // in a given array import java.io.*; import java.math.*; class GFG { // Function to check number is a // perfect square or not static boolean isPerfectSquare( int num) { int n = ( int )(Math.sqrt(num)); return (n * n == num); } // Function to check if the number // is in Fibonacci or not static void checkFib( int array[], int n) { int count = 0 ; for ( int i = 0 ; i < n; i++) { if (isPerfectSquare( 5 * array[i] * array[i] + 4 ) || isPerfectSquare( 5 * array[i] * array[i] - 4 )) { System.out.print(array[i] + " " ); count++; } } if (count == 0 ) System.out.println( "None Present" ); } // driver program public static void main(String[] args) { int array[] = { 4 , 2 , 8 , 5 , 20 , 1 , 40 , 13 , 23 }; int n = array.length; checkFib(array, n); } } // Contributed by Pramod Kumar |
Python3
# Python program to find # Fibonacci series numbers # in a given array. import math def isPerfectSquare(num): n = int (math.sqrt(num)) return (n * n = = num) # Function to check if the number # is in Fibonacci or not def checkFib(array, n): count = 0 for i in range (n): if (isPerfectSquare( 5 * array[i] * array[i] + 4 ) or isPerfectSquare( 5 * array[i] * array[i] - 4 )): print (array[i], " " , end = ""); count = count + 1 if (count = = 0 ): print ( "None present" ); # driver code array = [ 4 , 2 , 8 , 5 , 20 , 1 , 40 , 13 , 23 ] n = len (array) checkFib(array, n) # This code is contributed # by Anant Agarwal. |
C#
// C# program to find Fibonacci series // numbers in a given array using System; class GFG { // Function to check number is a // perfect square or not static bool isPerfectSquare( int num) { int n = ( int )(Math.Sqrt(num)); return (n * n == num); } // Function to check if the number // is in Fibonacci or not static void checkFib( int [] array, int n) { int count = 0; for ( int i = 0; i < n; i++) { if (isPerfectSquare(5 * array[i] * array[i] + 4) || isPerfectSquare(5 * array[i] * array[i] - 4)) { Console.Write(array[i] + " " ); count++; } } if (count == 0) Console.WriteLine( "None Present" ); } // driver program public static void Main() { int [] array = { 4, 2, 8, 5, 20, 1, 40, 13, 23 }; int n = array.Length; checkFib(array, n); } } // This code is contributed by Sam007 |
PHP
<?php // PHP program to find // Fibonacci series numbers // in a given array. // Function to check // number is a perfect // square or not function isPerfectSquare( $num ) { $n = (int)(sqrt( $num )); return ( $n * $n == $num ); } // Function to check // if the number is // in Fibonacci or not function checkFib( $array , $n ) { $count = 0; for ( $i = 0; $i < $n ; $i ++) { if (isPerfectSquare(5 * $array [ $i ] * $array [ $i ] + 4) || isPerfectSquare(5 * $array [ $i ] * $array [ $i ] - 4)) { echo $array [ $i ]. " " ; $count ++; } } if ( $count == 0) echo "None present\n" ; } // Driver Code $array = array (4, 2, 8, 5, 20, 1, 40, 13, 23); $n = sizeof( $array ); checkFib( $array , $n ); // This code is contributed by mits. ?> |
Javascript
<script> // Javascript program to find // Fibonacci series numbers // in a given array. // Function to check // number is a perfect // square or not function isPerfectSquare(num) { let n = parseInt(Math.sqrt(num)); return (n * n == num); } // Function to check // if the number is // in Fibonacci or not function checkFib(array, n) { let count = 0; for (let i = 0; i < n; i++) { if (isPerfectSquare(5 * array[i] * array[i] + 4) || isPerfectSquare(5 * array[i] * array[i] - 4)) { document.write(array[i] + " " ); count++; } } if (count == 0) document.write( "None present + <br>" ); } // Driver Code let array = [4, 2, 8, 5, 20, 1, 40, 13, 23]; let n = array.length; checkFib(array, n); // This code is contributed by _saurabh_jaiswal </script> |
Output
2 8 5 1 13
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