Determine the winner of a game of deleting Characters from a String

• Last Updated : 21 May, 2021

Given a numeric string str, the task is to determine the winner of the game when two players play a game optimally with the string as per the given conditions:

• Player 1 always starts first.
• In one turn, one player can remove the contiguous elements from the string and the number of elements removed will add up to his score. Player 1 will remove odd contiguous elements and Player 1 will remove even contiguous elements.
• Any player who is not able to make a move loses the game.
• After all the strings are removed, the player with the maximum score wins the game and if the scores are equal, then print “-1”.

Examples:

Input: str = “7788”
Output: -1
Explanation:
The first move for player 1 is to remove 77 and for player 2 it is 88. The score for both is 2. Hence -1.

Input: str = “8822”
Output: Player 2
Explanation:
There are no odd elements, so player 1 can’t make a move, so player 2 wins.

Approach: Follow the steps below in order to solve the problem:

1. Create an array A[] of size 10 to store the frequency of all the digits in the given string.
2. Iterate the given string and update the frequency of each digit in the above array.
3. Traverse the array A[] and take two variables as sum1 = 0 and sum2 = 0 to store the sum of scores.
4. Increment sum1 if the index is odd i.e., Player 1 turn, else increment sum2 if the index is even i.e., Player 2 turn.
5. After the above steps, check if sum1 is equal to sum2 then print -1 otherwise print the number of players who win the game on the basis of the score.

Below is the implementation of the above approach:

C++

 // C++ program for the above approach #include using namespace std;   // Function to find the winner of the // game when both players play optimally void determineWinner(string str) {     // Stores the frequency of all digit     vector A(10);       // Stores the scores of player1     // and player2 respectively     int sum1 = 0, sum2 = 0;       // Iterate to store frequencies     for (int i = 0; i < str.length(); i++) {         A[int(str[i]) - 48]++;     }       for (int i = 0; i <= 9; i++) {           // Turn for the player1         if (i % 2 != 0) {               // Add score of player1             sum1 = sum1 + A[i];         }         else {               // Add score of player2             sum2 = sum2 + A[i];         }     }       // Check if its a draw     if (sum1 == sum2) {         cout << "-1";     }       // If score of player 1 is greater     else if (sum1 > sum2) {         cout << "Player 1";     }       // Otherwise     else {         cout << "Player 2";     } }   // Driver Code int main() {     string str = "78787";     determineWinner(str);     return 0; }

Java

 // Java program for the above approach import java.util.*;   class GFG{   // Function to find the winner of the // game when both players play optimally static void determineWinner(String str) {           // Stores the frequency of all digit     int[] A = new int;       // Stores the scores of player1     // and player2 respectively     int sum1 = 0, sum2 = 0;       // Iterate to store frequencies     for(int i = 0; i < str.length(); i++)     {         A[(int)str.charAt(i) - 48]++;     }       for(int i = 0; i <= 9; i++)     {                   // Turn for the player1         if (i % 2 != 0)         {               // Add score of player1             sum1 = sum1 + A[i];         }         else         {               // Add score of player2             sum2 = sum2 + A[i];         }     }       // Check if its a draw     if (sum1 == sum2)     {         System.out.print("-1");     }       // If score of player 1 is greater     else if (sum1 > sum2)     {         System.out.print("Player 1");     }       // Otherwise     else     {         System.out.print("Player 2");     } }   // Driver code public static void main (String[] args) {     String str = "78787";           determineWinner(str); } }   // This code is contributed by offbeat

Python3

 # Python3 program for the above approach   # Function to find the winner of the # game when both players play optimally def determineWinner(str):       # Stores the frequency of all digit     A = [0 for i in range(9)];       # Stores the scores of player1     # and player2 respectively     sum1 = 0; sum2 = 0;       # Iterate to store frequencies     for i in range(0, len(str)):         A[int(str[i])] += 1;           for i in range(0, 9):           # Turn for the player1         if (i % 2 != 0):               # Add score of player1             sum1 = sum1 + A[i];         else:               # Add score of player2             sum2 = sum2 + A[i];               # Check if its a draw     if (sum1 == sum2):         print("-1");           # If score of player 1 is greater     elif(sum1 > sum2):         print("Player 1");           # Otherwise     else:         print("Player 2");       # Driver code if __name__ == '__main__':           str = "78787";       determineWinner(str);       # This code is contributed by Amit Katiyar

C#

 // C# program for the above approach using System; class GFG{   // Function to find the winner of the // game when both players play optimally static void determineWinner(String str) {           // Stores the frequency of all digit     int[] A = new int;       // Stores the scores of player1     // and player2 respectively     int sum1 = 0, sum2 = 0;       // Iterate to store frequencies     for(int i = 0; i < str.Length; i++)     {         A[(int)str[i] - 48]++;     }       for(int i = 0; i <= 9; i++)     {                   // Turn for the player1         if (i % 2 != 0)         {               // Add score of player1             sum1 = sum1 + A[i];         }         else         {               // Add score of player2             sum2 = sum2 + A[i];         }     }       // Check if its a draw     if (sum1 == sum2)     {         Console.Write("-1");     }       // If score of player 1 is greater     else if (sum1 > sum2)     {         Console.Write("Player 1");     }       // Otherwise     else     {         Console.Write("Player 2");     } }   // Driver code public static void Main(String[] args) {     String str = "78787";           determineWinner(str); } }   // This code is contributed by Rohit_ranjan

Javascript



Output:

Player 1

Time Complexity: O(N)
Auxiliary Space: O(N)

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