Deletion at different positions in a Circular Linked List
tGiven a Circular Linked List. The task is to write programs to delete nodes from this list present at:
- First position.
- Last Position.
- At any given position
.
Deleting first node from Singly Circular Linked List
Examples:
Input : 99->11->22->33->44->55->66 Output : 11->22->33->44->55->66 Input : 11->22->33->44->55->66 Output : 22->33->44->55->66

Deleting First Node from Circular Linked List
Approach:
- Take two pointers current and previous and traverse the list.
- Keep the pointer current fixed pointing to the first node and move previous until it reaches the last node.
- Once, the pointer previous reaches the last node, do the following:
- previous->next = current-> next
- head = previous -> next;
Implementation: Function to delete first node from singly circular linked list.
C++
// Function to delete First node of // Circular Linked List void DeleteFirst( struct Node** head) { struct Node *previous = *head, *firstNode = *head; // check if list doesn't have any node // if not then return if (*head == NULL) { printf ( "\nList is empty\n" ); return ; } // check if list have single node // if yes then delete it and return if (previous->next == previous) { *head = NULL; return ; } // traverse second node to first while (previous->next != *head) { previous = previous->next; } // now previous is last node and // first node(firstNode) link address // put in last node(previous) link previous->next = firstNode->next; // make second node as head node *head = previous->next; free (firstNode); return ; } |
Java
// Function to delete First node of // Circular Linked List static void DeleteFirst(Node head) { Node previous = head, firstNode = head; // Check if list doesn't have any node // if not then return if (head == null ) { System.out.printf( "\nList is empty\n" ); return ; } // Check if list have single node // if yes then delete it and return if (previous.next == previous) { head = null ; return ; } // Traverse second node to first while (previous.next != head) { previous = previous.next; } // Now previous is last node and // first node(firstNode) link address // put in last node(previous) link previous.next = firstNode.next; // Make second node as head node head = previous.next; System.gc(); return ; } // This code is contributed by aashish1995 |
Python3
# Function delete First node of # Circular Linked List def DeleteFirst(head): previous = head next = head # check list have any node # if not then return if (head = = None ) : print ( "\nList is empty" ) return None # check list have single node # if yes then delete it and return if (previous. next = = previous) : head = None return None # traverse second to first while (previous. next ! = head): previous = previous. next next = previous. next # now previous is last node and # next is first node of list # first node(next) link address # put in last node(previous) link previous. next = next . next # make second node as head node head = previous. next return head # This code is contributed by shivanisinghss2110 |
C#
using System; public class GFG{ static public // Function delete First node of // Circular Linked List static Node DeleteFirst(Node head) { Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { Console.Write( "\nList is empty\n" ); return null ; } // Check if list have single node // if yes then delete it and return if (previous.next == previous) { head = null ; return null ; } // Traverse second node to first while (previous.next != head) { previous = previous.next; next = previous.next; } // Now previous is last node and // first node(firstNode) link address // put in last node(previous) link previous.next = next.next; // Make second node as head node head = previous.next; return head; } // This code is contributed by shivanisinghss2110. c void Main (){ // Code } |
Javascript
<script> function DeleteFirst(head) { previous = head, firstNode = head; // Check if list doesn't have any node // if not then return if (head == null ) { document.write( "<br>List is empty<br>" ); return ; } // Check if list have single node // if yes then delete it and return if (previous.next == previous) { head = null ; return ; } // Traverse second node to first while (previous.next != head) { previous = previous.next; } // Now previous is last node and // first node(firstNode) link address // put in last node(previous) link previous.next = firstNode.next; // Make second node as head node head = previous.next; return ; } // This code is contributed by rag2127 </script> |
Time Complexity: O(N), where N is the number of nodes in the Linked List.
Auxiliary Space: O(1)
Deleting the last node of the Circular Linked List
Examples:
Input : 99->11->22->33->44->55->66 Output : 99->11->22->33->44->55 Input : 99->11->22->33->44->55 Output : 99->11->22->33->44

Delete last node from Circular Linked List
Approach:
- Take two pointers current and previous and traverse the list.
- Move both pointers such that next of previous is always pointing to current. Keep moving the pointers current and previous until current reaches the last node and previous is at the second last node.
- Once, the pointer current reaches the last node, do the following:
- previous->next = current-> next
- head = previous -> next;
Function to delete last node from the list:
C++
// Function delete last node of // Circular Linked List void DeleteLast( struct Node** head) { struct Node *current = *head, *temp = *head, *previous; // check if list doesn't have any node // if not then return if (*head == NULL) { printf ( "\nList is empty\n" ); return ; } // check if list have single node // if yes then delete it and return if (current->next == current) { *head = NULL; return ; } // move first node to last // previous while (current->next != *head) { previous = current; current = current->next; } previous->next = current->next; *head = previous->next; free (current); return ; } |
Java
// Function to delete last node of // Circular Linked List static Node DeleteLast(Node head) { Node current = head, temp = head, previous = null ; // Check if list doesn't have any node // if not then return if (head == null ) { System.out.printf( "\nList is empty\n" ); return null ; } // Check if list have single node // if yes then delete it and return if (current.next == current) { head = null ; return null ; } // Move first node to last // previous while (current.next != head) { previous = current; current = current.next; } previous.next = current.next; head = previous.next; return head; } // This code is contributed by pratham76 |
Python3
# Function to delete last node of # Circular Linked List def DeleteLast(head): current = head temp = head previous = None # check if list doesn't have any node # if not then return if (head = = None ): print ( "\nList is empty" ) return None # check if list have single node # if yes then delete it and return if (current. next = = current): head = None return None # move first node to last # previous while (current. next ! = head): previous = current current = current. next previous. next = current. next head = previous. next return head # This code is contributed by rutvik_56 |
C#
// Function to delete last node of // Circular Linked List static Node DeleteLast(Node head) { Node current = head, temp = head, previous = null ; // check if list doesn't have any node // if not then return if (head == null ) { Console.Write( "\nList is empty\n" ); return null ; } // check if list have single node // if yes then delete it and return if (current.next == current) { head = null ; return null ; } // move first node to last // previous while (current.next != head) { previous = current; current = current.next; } previous.next = current.next; head = previous.next; return head; } // This code is contributed by shivanisinghss2110 |
Javascript
<script> function DeleteLast(head) { let current = head, temp = head, previous = null ; // Check if list doesn't have any node // if not then return if (head == null ) { document.write( "<br>List is empty<br>" ); return null ; } // Check if list have single node // if yes then delete it and return if (current.next == current) { head = null ; return null ; } // Move first node to last // previous while (current.next != head) { previous = current; current = current.next; } previous.next = current.next; head = previous.next; return head; } // This code is contributed by avanitrachhadiya2155 </script> |
Time Complexity: O(N) where N is the number of nodes in given Linked List.
Auxiliary Space: O(1)
Deleting nodes at given index in the Circular linked list
Examples:
Input : 99->11->22->33->44->55->66 Index= 4 Output : 99->11->22->33->55->66 Input : 99->11->22->33->44->55->66 Index= 2 Output : 99->11->33->44->55->66
Note: 0-based indexing is considered for the list.
Approach:
- First, find the length of the list. That is, the number of nodes in the list.
- Take two pointers previous and current to traverse the list. Such that previous is one position behind the current node.
- Take a variable count initialized to 0 to keep track of the number of nodes traversed.
- Traverse the list until the given index is reached.
- Once the given index is reached, do previous->next = current->next.
Function to delete a node at given index or location from singly circular linked list:
C++
// Function to delete node at given index // of Circular Linked List void DeleteAtPosition(Node* head, int index) { // find length of list int len = Length(head); int count = 1; Node* previous = head; Node* next = head; // check if list doesn't have any node // if not then return if (head == NULL){ cout<< "Delete Last list is empty" ; return ; } // given index is in list or not if (index >= len || index<0){ cout<< "Index is not Found" ; return ; } // delete first node if (index == 0){ DeleteFirst(head); return ; } // traverse first to last node while (len > 0){ // if index found delete that node if (index == count){ previous->next = next->next; free (next); return ; } previous = previous->next; next = previous->next; len--; count++; } return ; } // This code is contributed by Yash Agarwal(yashagarwal2852002) |
C
// Function to delete node at given index // of Circular Linked List void DeleteAtPosition( struct Node** head, int index) { // find length of list int len = Length(*head); int count = 1; struct Node *previous = *head, *next = *head; // check if list doesn't have any node // if not then return if (*head == NULL) { printf ( "\nDelete Last List is empty\n" ); return ; } // given index is in list or not if (index >= len || index < 0) { printf ( "\nIndex is not Found\n" ); return ; } // delete first node if (index == 0) { DeleteFirst(head); return ; } // traverse first to last node while (len > 0) { // if index found delete that node if (index == count) { previous->next = next->next; free (next); return ; } previous = previous->next; next = previous->next; len--; count++; } return ; } |
Java
// Java program to delete node at different // Function delete node at a given position // of Circular Linked List static Node DeleteAtPosition( Node head, int index) { // Find length of list int len = Length(head); int count = 1 ; Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { System.out.printf( "\nDelete Last List is empty\n" ); return null ; } // given index is in list or not if (index >= len || index < 0 ) { System.out.printf( "\nIndex is not Found\n" ); return null ; } // delete first node if (index == 0 ) { head = DeleteFirst(head); return head; } // traverse first to last node while (len > 0 ) { // if index found delete that node if (index == count) { previous.next = next.next; return head; } previous = previous.next; next = previous.next; len--; count++; } return head; } // This code is contributed by shivanisinghss2110 |
Python3
# Function delete node at a given position # of Circular Linked List def DeleteAtPosition(head, index): # Find length of list len = Length(head) count = 1 previous = head next = head # check list have any node # if not then return if (head = = None ): print ( "\nDelete Last List is empty" ) return None # given index is in list or not if (index > = len or index < 0 ) : print ( "\nIndex is not Found" ) return None # delete first node if (index = = 0 ) : head = DeleteFirst(head) return head # traverse first to last node while ( len > 0 ): # if index found delete that node if (index = = count): previous. next = next . next return head previous = previous. next next = previous. next len = len - 1 count = count + 1 return head # This code is contributed by shivanisinghss2110 |
C#
// C# program to delete node at given index // of circular linked list static void DeleteAtPosition(Node head, int index) { // find length of list int len = Length(head); int count = 1; Node previous = head; Node next = head; // check if list doesn't have any node // if noth then return if (head == null ) { Console.Write( "Delete Last list is empty" ); return ; } // given index is in list or not if (index >= len || index < 0) { Console.Write( "Index is not Found" ); return ; } // delete first node if (index == 0) { DeleteFirst(head); return ; } // traverse first to last node while (len > 0) { // if index found delete that node if (index == count) { previous.next = next.next; return ; } previous = previous.next; next = previous.next; len -= 1; count++; } } // this code is contributed by Kirti // Agarwal(kirtiagarwal23121999) |
Javascript
<script> // Function delete node at a given position // of Circular Linked List function DeleteAtPosition(head, index){ // Find length of list let len = head.length let count = 1 let previous = head let next = head // check list have any node // if not then return if (head == null ){ document.write( "</br>" , "Delete Last List is empty" ) return null } // given index is in list or not if (index >= len || index < 0){ document.write( "</br>" , "Index is not Found" ) return null } // delete first node if (index == 0){ head = DeleteFirst(head) return head } // traverse first to last node while (len > 0){ // if index found delete that node if (index == count){ previous.next = next.next return head } previous = previous.next next = previous.next len = len - 1 count = count + 1 } return head } // This code is contributed by shinjanpatra </script> |
Time Complexity: O(N)
Auxiliary Space: O(1)
Program implementing all of the above three functions
C++
// C++ program to delete node at different // positions from a circular linked list #include <bits/stdc++.h> using namespace std; // structure for a node struct Node { int data; struct Node* next; }; // Function to insert a node at the end of // a Circular linked list void Insert( struct Node** head, int data) { struct Node* current = *head; // Create a new node struct Node* newNode = new Node; // check node is created or not if (!newNode) { printf ( "\nMemory Error\n" ); return ; } // insert data into newly created node newNode->data = data; // check list is empty // if not have any node then // make first node it if (*head == NULL) { newNode->next = newNode; *head = newNode; return ; } // if list have already some node else { // move first node to last node while (current->next != *head) { current = current->next; } // put first or head node address // in new node link newNode->next = *head; // put new node address into last // node link(next) current->next = newNode; } } // Function print data of list void Display( struct Node* head) { struct Node* current = head; // if list is empty, simply show message if (head == NULL) { printf ( "\nDisplay List is empty\n" ); return ; } // traverse first to last node else { do { printf ( "%d " , current->data); current = current->next; } while (current != head); } } // Function return number of nodes present in list int Length( struct Node* head) { struct Node* current = head; int count = 0; // if list is empty simply return length zero if (head == NULL) { return 0; } // traverse first to last node else { do { current = current->next; count++; } while (current != head); } return count; } // Function delete First node of Circular Linked List void DeleteFirst( struct Node** head) { struct Node *previous = *head, *next = *head; // check list have any node // if not then return if (*head == NULL) { printf ( "\nList is empty\n" ); return ; } // check list have single node // if yes then delete it and return if (previous->next == previous) { *head = NULL; return ; } // traverse second to first while (previous->next != *head) { previous = previous->next; next = previous->next; } // now previous is last node and // next is first node of list // first node(next) link address // put in last node(previous) link previous->next = next->next; // make second node as head node *head = previous->next; free (next); return ; } // Function to delete last node of // Circular Linked List void DeleteLast( struct Node** head) { struct Node *current = *head, *temp = *head, *previous; // check if list doesn't have any node // if not then return if (*head == NULL) { printf ( "\nList is empty\n" ); return ; } // check if list have single node // if yes then delete it and return if (current->next == current) { *head = NULL; return ; } // move first node to last // previous while (current->next != *head) { previous = current; current = current->next; } previous->next = current->next; *head = previous->next; free (current); return ; } // Function delete node at a given position // of Circular Linked List void DeleteAtPosition( struct Node** head, int index) { // Find length of list int len = Length(*head); int count = 1; struct Node *previous = *head, *next = *head; // check list have any node // if not then return if (*head == NULL) { printf ( "\nDelete Last List is empty\n" ); return ; } // given index is in list or not if (index >= len || index < 0) { printf ( "\nIndex is not Found\n" ); return ; } // delete first node if (index == 0) { DeleteFirst(head); return ; } // traverse first to last node while (len > 0) { // if index found delete that node if (index == count) { previous->next = next->next; free (next); return ; } previous = previous->next; next = previous->next; len--; count++; } return ; } // Driver Code int main() { struct Node* head = NULL; Insert(&head, 99); Insert(&head, 11); Insert(&head, 22); Insert(&head, 33); Insert(&head, 44); Insert(&head, 55); Insert(&head, 66); // Deleting Node at position printf ( "Initial List: " ); Display(head); printf ( "\nAfter Deleting node at index 4: " ); DeleteAtPosition(&head, 4); Display(head); // Deleting first Node printf ( "\n\nInitial List: " ); Display(head); printf ( "\nAfter Deleting first node: " ); DeleteFirst(&head); Display(head); // Deleting last Node printf ( "\n\nInitial List: " ); Display(head); printf ( "\nAfter Deleting last node: " ); DeleteLast(&head); Display(head); return 0; } |
Java
// Java implementation to delete node at different // positions from a circular linked list import java.util.*; public class GFG { // structure for a node static class Node { int data; Node next; }; // Function to insert a node at the end of // a Circular linked list static Node Insert(Node head, int data){ Node current = head; // Create a new node Node newNode = new Node(); // check node is created or not if (newNode == null ) { System.out.printf( "\nMemory Error\n" ); return null ; } // insert data into newly created node newNode.data = data; // check list is empty // if not have any node then // make first node it if (head == null ) { newNode.next = newNode; head = newNode; return head; } else { // move first node to last node while (current.next != head) { current = current.next; } // put first or head node address // in new node link newNode.next = head; // put new node address into last // node link(next) current.next = newNode; } return head; } // function to print the data of linked list static void Display(Node head){ Node current = head; // if list is empty, simply show message if (head == null ) { System.out.printf( "\nDisplay List is empty\n" ); return ; } else { do { System.out.printf( "%d " , current.data); current = current.next; } while (current != head); } } // returns the number of nodes present in the linked list static int Length(Node head){ Node current = head; int count = 0 ; // if list is empty // simply return length zero if (head == null ) return 0 ; else { do { current = current.next; count++; } while (current != head); } return count; } // function to delete First node of // circular Linked List static Node DeleteFirst(Node head){ Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { System.out.printf( "\nList is empty\n" ); return null ; } // check list have single node // if yes then delete it and return if (previous.next == previous) { head = null ; return null ; } // traverse second to first while (previous.next != head) { previous = previous.next; next = previous.next; } // now previous is last node and // next is first node of list // first node(next) link address // put in last node(previous) link previous.next = next.next; // make second node as head node head = previous.next; return head; } // Function to delete last node of // Circular Linked List static Node DeleteLast(Node head){ Node current = head, temp = head, previous = null ; // check if list doesn't have any node // if not then return if (head == null ) { System.out.printf( "\nList is empty\n" ); return null ; } // check if list have single node // if yes then delete it and return if (current.next == current) { head = null ; return null ; } // move first node to last // previous while (current.next != head) { previous = current; current = current.next; } previous.next = current.next; head = previous.next; return head; } // Function delete node at a given position // of Circular Linked List static Node DeleteAtPosition(Node head, int index){ // Find length of list int len = Length(head); int count = 1 ; Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { System.out.printf( "\nDelete Last List is empty\n" ); return null ; } // given index is in list or not if (index >= len || index < 0 ) { System.out.printf( "\nIndex is not Found\n" ); return null ; } // delete first node if (index == 0 ) { head = DeleteFirst(head); return head; } // traverse first to last node while (len > 0 ) { // if index found delete that node if (index == count) { previous.next = next.next; return head; } previous = previous.next; next = previous.next; len--; count++; } return head; } // Driver Code public static void main(String args[]) { Node head = null ; head = Insert(head, 99 ); head = Insert(head, 11 ); head = Insert(head, 22 ); head = Insert(head, 33 ); head = Insert(head, 44 ); head = Insert(head, 55 ); head = Insert(head, 66 ); // Deleting Node at position System.out.printf( "Initial List: " ); Display(head); System.out.printf( "\nAfter Deleting node at index 4: " ); head = DeleteAtPosition(head, 4 ); Display(head); // Deleting first Node System.out.printf( "\n\nInitial List: " ); Display(head); System.out.printf( "\nAfter Deleting first node: " ); head = DeleteFirst(head); Display(head); // Deleting last Node System.out.printf( "\n\nInitial List: " ); Display(head); System.out.printf( "\nAfter Deleting last node: " ); head = DeleteLast(head); Display(head); } } // THIS CODE IS CONTRIBUTED BY YASH AGARWAL(YASHAGARWAL2852002) |
Python3
# Python3 program to delete node at different # positions from a circular linked list # A linked list node class Node: def __init__( self , new_data): self .data = new_data self . next = None self .prev = None # Function to insert a node at the end of # a Circular linked list def Insert(head, data): current = head # Create a new node newNode = Node( 0 ) # check node is created or not if (newNode = = None ): print ( "\nMemory Error\n" ) return None # insert data into newly created node newNode.data = data # check list is empty # if not have any node then # make first node it if (head = = None ) : newNode. next = newNode head = newNode return head # if list have already some node else : # move first node to last node while (current. next ! = head): current = current. next # put first or head node address # in new node link newNode. next = head # put new node address into last # node link(next) current. next = newNode return head # Function print data of list def Display(head): current = head # if list is empty, simply show message if (head = = None ): print ( "\nDisplay List is empty\n" ) return # traverse first to last node else : while ( True ): print ( current.data,end = " " ) current = current. next if (current = = head): break ; # Function return number of nodes present in list def Length(head): current = head count = 0 # if list is empty # simply return length zero if (head = = None ): return 0 # traverse first to last node else : while ( True ): current = current. next count = count + 1 if (current = = head): break ; return count # Function delete First node of # Circular Linked List def DeleteFirst(head): previous = head next = head # check list have any node # if not then return if (head = = None ) : print ( "\nList is empty" ) return None # check list have single node # if yes then delete it and return if (previous. next = = previous) : head = None return None # traverse second to first while (previous. next ! = head): previous = previous. next next = previous. next # now previous is last node and # next is first node of list # first node(next) link address # put in last node(previous) link previous. next = next . next # make second node as head node head = previous. next return head # Function to delete last node of # Circular Linked List def DeleteLast(head): current = head temp = head previous = None # check if list doesn't have any node # if not then return if (head = = None ): print ( "\nList is empty" ) return None # check if list have single node # if yes then delete it and return if (current. next = = current) : head = None return None # move first node to last # previous while (current. next ! = head): previous = current current = current. next previous. next = current. next head = previous. next return head # Function delete node at a given position # of Circular Linked List def DeleteAtPosition(head, index): # Find length of list len = Length(head) count = 1 previous = head next = head # check list have any node # if not then return if (head = = None ): print ( "\nDelete Last List is empty" ) return None # given index is in list or not if (index > = len or index < 0 ) : print ( "\nIndex is not Found" ) return None # delete first node if (index = = 0 ) : head = DeleteFirst(head) return head # traverse first to last node while ( len > 0 ): # if index found delete that node if (index = = count): previous. next = next . next return head previous = previous. next next = previous. next len = len - 1 count = count + 1 return head # Driver Code head = None head = Insert(head, 99 ) head = Insert(head, 11 ) head = Insert(head, 22 ) head = Insert(head, 33 ) head = Insert(head, 44 ) head = Insert(head, 55 ) head = Insert(head, 66 ) # Deleting Node at position print ( "Initial List: " ) Display(head) print ( "\nAfter Deleting node at index 4: " ) head = DeleteAtPosition(head, 4 ) Display(head) # Deleting first Node print ( "\n\nInitial List: " ) Display(head) print ( "\nAfter Deleting first node: " ) head = DeleteFirst(head) Display(head) # Deleting last Node print ( "\n\nInitial List: " ) Display(head) print ( "\nAfter Deleting last node: " ) head = DeleteLast(head) Display(head) # This code is contributed by Arnab Kundu |
C#
// C# program to delete node at different // positions from a circular linked list using System; class GFG { // structure for a node class Node { public int data; public Node next; }; // Function to insert a node at the end of // a Circular linked list static Node Insert(Node head, int data) { Node current = head; // Create a new node Node newNode = new Node(); // check node is created or not if (newNode == null ) { Console.Write( "\nMemory Error\n" ); return null ; } // insert data into newly created node newNode.data = data; // check list is empty // if not have any node then // make first node it if (head == null ) { newNode.next = newNode; head = newNode; return head; } // if list have already some node else { // move first node to last node while (current.next != head) { current = current.next; } // put first or head node address // in new node link newNode.next = head; // put new node address into last // node link(next) current.next = newNode; } return head; } // Function print data of list static void Display( Node head) { Node current = head; // if list is empty, simply show message if (head == null ) { Console.Write( "\nDisplay List is empty\n" ); return ; } // traverse first to last node else { do { Console.Write( "{0} " , current.data); current = current.next; } while (current != head); } } // Function return number of nodes present in list static int Length(Node head) { Node current = head; int count = 0; // if list is empty // simply return length zero if (head == null ) { return 0; } // traverse first to last node else { do { current = current.next; count++; } while (current != head); } return count; } // Function delete First node of // Circular Linked List static Node DeleteFirst(Node head) { Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { Console.Write( "\nList is empty\n" ); return null ; } // check list have single node // if yes then delete it and return if (previous.next == previous) { head = null ; return null ; } // traverse second to first while (previous.next != head) { previous = previous.next; next = previous.next; } // now previous is last node and // next is first node of list // first node(next) link address // put in last node(previous) link previous.next = next.next; // make second node as head node head = previous.next; return head; } // Function to delete last node of // Circular Linked List static Node DeleteLast(Node head) { Node current = head, temp = head, previous = null ; // check if list doesn't have any node // if not then return if (head == null ) { Console.Write( "\nList is empty\n" ); return null ; } // check if list have single node // if yes then delete it and return if (current.next == current) { head = null ; return null ; } // move first node to last // previous while (current.next != head) { previous = current; current = current.next; } previous.next = current.next; head = previous.next; return head; } // Function delete node at a given position // of Circular Linked List static Node DeleteAtPosition( Node head, int index) { // Find length of list int len = Length(head); int count = 1; Node previous = head, next = head; // check list have any node // if not then return if (head == null ) { Console.Write( "\nDelete Last List is empty\n" ); return null ; } // given index is in list or not if (index >= len || index < 0) { Console.Write( "\nIndex is not Found\n" ); return null ; } // delete first node if (index == 0) { head = DeleteFirst(head); return head; } // traverse first to last node while (len > 0) { // if index found delete that node if (index == count) { previous.next = next.next; return head; } previous = previous.next; next = previous.next; len--; count++; } return head; } // Driver Code public static void Main(String []args) { Node head = null ; head = Insert(head, 99); head = Insert(head, 11); head = Insert(head, 22); head = Insert(head, 33); head = Insert(head, 44); head = Insert(head, 55); head = Insert(head, 66); // Deleting Node at position Console.Write( "Initial List: " ); Display(head); Console.Write( "\nAfter Deleting node at index 4: " ); head = DeleteAtPosition(head, 4); Display(head); // Deleting first Node Console.Write( "\n\nInitial List: " ); Display(head); Console.Write( "\nAfter Deleting first node: " ); head = DeleteFirst(head); Display(head); // Deleting last Node Console.Write( "\n\nInitial List: " ); Display(head); Console.Write( "\nAfter Deleting last node: " ); head = DeleteLast(head); Display(head); } } // This code is contributed by Rajput-Ji |
Javascript
<script> // JavaScript program to delete node at different // positions from a circular linked list // A linked list node class Node{ constructor(new_data){ this .data = new_data this .next = null this .prev = null } } // Function to insert a node at the end of // a Circular linked list function Insert(head, data){ let current = head // Create a new node let newNode = new Node(0) // check node is created or not if (newNode == null ){ document.write( "</br>" , "Memory Error" , "</br>" ) return null } // insert data into newly created node newNode.data = data // check list is empty // if not have any node then // make first node it if (head == null ){ newNode.next = newNode head = newNode return head } // if list have already some node else { // move first node to last node while (current.next != head) current = current.next // put first or head node address // in new node link newNode.next = head // put new node address into last // node link(next) current.next = newNode } return head } // Function document.write data of list function Display(head){ let current = head // if list is empty, simply show message if (head == null ){ document.write( "</br>" , "Display List is empty" , "</br>" ) return } // traverse first to last node else { while ( true ){ document.write( current.data, " " ) current = current.next if (current == head) break ; } } } // Function return number of nodes present in list function Length(head){ let current = head let count = 0 // if list is empty // simply return length zero if (head == null ) return 0 // traverse first to last node else { while ( true ){ current = current.next count = count + 1 if (current == head) break ; } } return count } // Function delete First node of // Circular Linked List function DeleteFirst(head){ let previous = head let next = head // check list have any node // if not then return if (head == null ){ document.write( "</br>" , "List is empty" ) return null } // check list have single node // if yes then delete it and return if (previous.next == previous){ head = null return null } // traverse second to first while (previous.next != head){ previous = previous.next next = previous.next } // now previous is last node and // next is first node of list // first node(next) link address // put in last node(previous) link previous.next = next.next // make second node as head node head = previous.next return head } // Function to delete last node of // Circular Linked List function DeleteLast(head){ let current = head let temp = head let previous = null // check if list doesn't have any node // if not then return if (head == null ){ document.write( "</br>" , "List is empty" ) return null } // check if list have single node // if yes then delete it and return if (current.next == current){ head = null return null } // move first node to last // previous while (current.next != head){ previous = current current = current.next } previous.next = current.next head = previous.next return head } // Function delete node at a given position // of Circular Linked List function DeleteAtPosition(head, index){ // Find length of list len = Length(head) count = 1 previous = head next = head // check list have any node // if not then return if (head == null ){ document.write( "</br>" , "Delete Last List is empty" ) return null } // given index is in list or not if (index >= len || index < 0) { document.write( "</br>" , "Index is not Found" ) return null } // delete first node if (index == 0){ head = DeleteFirst(head) return head } // traverse first to last node while (len > 0){ // if index found delete that node if (index == count){ previous.next = next.next return head } previous = previous.next next = previous.next len = len - 1 count = count + 1 } return head } // Driver Code let head = null head = Insert(head, 99) head = Insert(head, 11) head = Insert(head, 22) head = Insert(head, 33) head = Insert(head, 44) head = Insert(head, 55) head = Insert(head, 66) // Deleting Node at position document.write( "Initial List: " ) Display(head) document.write( "</br>" , "After Deleting node at index 4: " ) head = DeleteAtPosition(head, 4) Display(head) // Deleting first Node document.write( "</br>" , "</br>" , "Initial List: " ) Display(head) document.write( "</br>" , "After Deleting first node: " ) head = DeleteFirst(head) Display(head) // Deleting last Node document.write( "</br>" , "</br>" , "Initial List: " ) Display(head) document.write( "</br>" , "After Deleting last node: " ) head = DeleteLast(head) Display(head) // This code is contributed by shinjanpatra </script> |
Initial List: 99 11 22 33 44 55 66 After Deleting node at index 4: 99 11 22 33 55 66 Initial List: 99 11 22 33 55 66 After Deleting first node: 11 22 33 55 66 Initial List: 11 22 33 55 66 After Deleting last node: 11 22 33 55
Time Complexity: O(N) where N is the number of nodes in given linked list.
Auxiliary Space: O(1)
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