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Data Structures | Heap | Question 9

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  • Last Updated : 28 Jun, 2021
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In a binary max heap containing n numbers, the smallest element can be found in time 

(A)

0(n)

(B)

O(logn)

(C)

0(loglogn)

(D)

0(1)


Answer: (A)

Explanation:

In a max heap, the smallest element is always present at a leaf node. So we need to check for all leaf nodes for the minimum value. Worst case complexity will be O(n)

         12
        /  \\
      /      \\
    8         7
   / \\        / \\
 /     \\    /     \\
2      3   4       5


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