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C++ Program For Writing A Function To Get Nth Node In A Linked List

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  • Last Updated : 27 Mar, 2023
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Write a GetNth() function that takes a linked list and an integer index and returns the data value stored in the node at that index position. 

Example: 

Input:  1->10->30->14,  index = 2
Output: 30  
The node at index 2 is 30

Algorithm: 

1. Initialize count = 0
2. Loop through the link list
     a. If count is equal to the passed index then return current
         node
     b. Increment count
     c. change current to point to next of the current.

Implementation: 

C++




// C++ program to find n'th
// node in linked list
#include <assert.h>
#include <bits/stdc++.h>
using namespace std;
 
// Link list node
class Node
{
    public:
    int data;
    Node* next;
};
 
/* Given a reference (pointer to
pointer) to the head of a list
and an int, push a new node on
the front of the list. */
void push(Node** head_ref,
          int new_data)
{
    // Allocate node
    Node* new_node = new Node();
 
    // Put in the data
    new_node->data = new_data;
 
    // Link the old list
    // of the new node
    new_node->next = (*head_ref);
 
    // Move the head to point
    // to the new node
    (*head_ref) = new_node;
}
 
// Takes head pointer of
// the linked list and index
// as arguments and return
// data at index
int GetNth(Node* head, int index)
{
    Node* current = head;
 
    // The index of the
    // node we're currently
    // looking at
    int count = 0;
    while (current != NULL)
    {
        if (count == index)
            return (current->data);
        count++;
        current = current->next;
    }
 
    /* If we get to this line,
    the caller was asking
    for a non-existent element
    so we assert fail */
    assert(0);
}
 
// Driver Code
int main()
{
    // Start with the empty list
    Node* head = NULL;
 
    // Use push() to construct list
    // 1->12->1->4->1
    push(&head, 1);
    push(&head, 4);
    push(&head, 1);
    push(&head, 12);
    push(&head, 1);
 
    // Check the count function
    cout << "Element at index 3 is " <<
             GetNth(head, 3);
    return 0;
}
// This code is contributed by rathbhupendra


Output:

Element at index 3 is 4

Time Complexity: O(n)

Space complexity: O(1) using only constant variables

Method 2- With Recursion: 
This method is contributed by MY_DOOM

Algorithm:  

getnth(node,n)
1. Initialize count = 0
2. if count==n
     return node->data
3. else
    return getnth(node->next,n-1)

Implementation: 

C++




// C++ program to find n'th node in
// linked list using recursion
#include <bits/stdc++.h>
using namespace std;
 
// Link list node
struct Node
{
    int data;
    struct Node* next;
};
 
/*  Given a reference (pointer to pointer)
    to the head of a list and an int, push
    a new node on the front of the list. */
void push(struct Node** head_ref,
          int new_data)
{
    // Allocate node
    struct Node* new_node =
           (struct Node*)malloc(sizeof(struct Node));
 
    // Put in the data
    new_node->data = new_data;
 
    // Link the old list of the new node
    new_node->next = (*head_ref);
 
    // Move the head to point to the new node
    (*head_ref) = new_node;
}
 
/* Takes head pointer of the linked list and
   index as arguments and return data at index.
   (Don't use another variable)*/
int GetNth(struct Node* head, int n)
{
    // If length of the list is less
    // than the given index, return -1
    if (head == NULL)
        return -1;
 
    // If n equal to 0 return node->data
    if (n == 0)
        return head->data;
 
    // Increase head to next pointer
    // n - 1: decrease the number of
    // recursions until n = 0
    return GetNth(head->next, n - 1);
}
 
// Driver code
int main()
{
    // Start with the empty list
    struct Node* head = NULL;
 
    // Use push() to construct list
    // 1->12->1->4->1
    push(&head, 1);
    push(&head, 4);
    push(&head, 1);
    push(&head, 12);
    push(&head, 1);
 
    // Check the count function
    printf("Element at index 3 is %d",
            GetNth(head, 3));
    getchar();
}


Output:

Element at index 3 is 4

Time Complexity: O(n) 

Space Complexity: O(n) since using constant space to create nodes

Please refer complete article on Write a function to get Nth node in a Linked List for more details!


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