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Convert given Binary Array to String in C++ with Examples

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  • Difficulty Level : Easy
  • Last Updated : 08 Dec, 2021

Given a binary array arr[] containing N integer elements, the task is to create a string s which contains all N elements at the same indices as they were in array arr[].

Example:

Input: arr[] = {0, 1, 0, 1}
Output: string = “0101

Input: arr[] = { 1, 1, 0, 0, 1, 1}
Output: string = “110011”

 

Different methods to convert a binary array to a string in C++ are:

  1. Using to_string() function.
  2. Using string stream.
  3. Adding char ‘0’ to each integer.
  4. Using type casting.
  5. Using push_back function.
  6. Using transform() function.

Let’s start discussing each of these functions in detail.

Using to_string() function

The to_string() function accepts a single integer and converts the integer value into a string.

Syntax:

string to_string (int val);

Parameters:
val – Numerical value.

Return Value:
A string object containing the representation of val as a sequence of characters.

Below is the C++ program to implement the above approach:

C++




// C++ program to implement
// the above approach
#include <iostream>
#include <string>
using namespace std;
  
// Driver code
int main()
{
  int arr[5] = {1, 0, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
    
  // Creating an empty string
  string s = "";
  for(int i = 0; i < size; i++) 
  {
    s += to_string(arr[i]);
  }
    
  cout << s;
  return 0;
}


Output:

10101

Using string stream

stringstream class is extremely useful in parsing input. A stringstream associates a string object with a stream allowing you to read from the string as if it were a stream (like cin). To use stringstream class the sstream header file needs to be included in the code.

Basic methods  are:

clear(): to clear the stream

str(): to get and set string object whose content is present in stream.

operator << add a string to the stringstream object.

operator >> read something from the stringstream object,

The stringstream class can be used to convert the integer value into a string value in the following manner:

  1. Insert data into the stream using ‘<<‘ operator.
  2. Extract data from stream using ‘>>’ operator or by using str() function.
  3. Concatenate the extracted data with the string ‘s’.

Below is the C++ program to implement the above approach:

C++




// C++ program to implement
// the above approach
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
  
// Driver code
int main()
{
  int arr[5] = {1, 0, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
    
  // Creating an empty string
  string s = "";
  for(int i = 0; i < size; i++) 
  {
    // Creating an empty stringstream
    stringstream temp;
      
    // Inserting data into the stream
    temp << arr[i];
      
    // Extracting data from stream using 
    // .str() function
    s += temp.str();
  }
    
  // Printing the string 
  cout << s;
}


Output:

10101

Adding char ‘0’ to each Integer

The approach for adding char ‘0’ to each integer is quite simple.

  1. First step is to declare an empty string s.
  2. Iterate over each element of array and concatenate each integer by adding ASCII Value of char ‘0’ with the string s.

Logic:
The result of adding ASCII value of char ‘0’ with integer 0 and 1 is computed by compiler as follows:

Decimal value of char ‘0’ is 48.

string += 0 + ‘0’
      // += 0 + 48 
      // += 48
Char value of decimal 48 is ‘0’.

string += 1 + ‘0’
      // += 1 + 48
      // += 49
Char value of decimal 49 is ‘1’.

Below is the C++ program to implement the above approach:

C++




// C++ program to implement 
// the above approach
#include <iostream>
#include <string>
using namespace std;
  
// Driver code
int main() 
{
  int arr[5] = {1, 1, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
  string s = "";
    
  // Creating an empty string
  for(int i = 0; i < size; i++) 
  {
    // arr[i] + 48
    // adding ASCII of value of 0 
    // i.e., 48
    s += arr[i] + '0'
  }
    
  // Printing the string 
  cout << s;
}


Output:

11101

Using type casting

Before type casting and concatenating there is a need to add 48 to the integer otherwise it will lead to some weird symbols at the output. This happens because in the ASCII table numbers from 0 to 9 have a char value that starts from 48 to 57. In the case of a binary array, the integer will either be 0 or 1.

  1. If it is 0, after adding it will be 48 then after type casting char ‘0’ is concatenated with string.
  2. If it is 1, after adding it will be 49 then after type casting char ‘1’ is concatenated with string.

Below is the C++ program to implement the above approach:

C++




// C++ program to implement
// the above approach
#include <iostream>
#include <string>
using namespace std;
  
// Driver code
int main()
{
  int arr[5] = {1, 1, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
    
  // Creating an empty string
  string s = "";
  for(int i = 0; i < size; i++) 
  {
    arr[i] += 48;
    s += (char) arr[i];
  }
    
  // Printing the string
  cout << s;
}


Output:

11101

Using push_back() function

The push_back() member function is provided to append characters. Appends character c to the end of the string, increasing its length by one.

Syntax:

void string:: push_back (char c)

Parameters:  
Character which to be appended.  

Return value: 
None

Error: 
throws length_error if the resulting size exceeds the maximum number of characters(max_size).

Note:
Logic behind adding char ‘0’ has been discussed in Method “Adding ‘0’ to integer”.

Below is the C++ program to implement the above approach:

C++




// C++ program to implement 
// the above approach
#include <iostream>
#include <vector>
using namespace std;
  
// Driver code
int main() 
{
  int arr[5] = {1, 0, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
  vector<char> s;
  for(int i = 0; i < size; i++) 
  {
    s.push_back(arr[i] + '0');
  }
  for(auto it : s) 
  {
    cout << it;
  }
}


Output:

10101

Using transform() function

The transform() function sequentially applies an operation to the elements of an array and store the result in another output array. To use the transform() function include the algorithm header file. 

Below is the C++ program to implement the above method:

C++




// C++ program to implement
// the above method
#include <iostream>
#include <algorithm>
using namespace std;
  
// define int to char function
char intToChar(int i) 
{
  // logic behind adding 48 to integer 
  // is discussed in Method "using type
  // casting".
  return i + 48;
}
  
// Driver code
int main() 
{
  int arr[5] = {1, 0, 1, 0, 1};
  int size = sizeof(arr) / sizeof(arr[0]);
  char str[size + 1]; 
  transform(arr, arr + 5, str, intToChar);
    
  // Printing the string
  cout << str;
}


Output:

10101


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