Open in App
Not now

# Class 10 NCERT Solutions – Chapter 14 Statistics – Exercise 14.1

• Last Updated : 15 Dec, 2020

### Which method did you use for finding the mean, and why?

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: Now, we will multiply the classmark with the number of times they have occurred, i.e, with the frequency.

Step 3: Now we will apply the general formula to calculate the mean

Now, Let’s see the detailed solution:

Now, after creating this table we will be able to find the mean very easily –

= 16

= 8.1

Hence, we come to the conclusion that the number of plants per house is 8.1. Since the numeral value of frequency(fi) and the class mark(xi) is small so we use DIRECT METHOD to find the mean number of plants per house.

### Find the mean daily wages of the workers of the factory by using an appropriate method.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: In this case, the value of mid-point (xi) is very large, so let us assume the mean value, A = 150, and the class interval is h = 20.

ui = (xi â€“ A)/h

=> ui = (xi â€“ 150)/20

Step 3: Now we will apply the Assumed Mean Formula to calculate the mean

Now, Let’s see the detailed solution:

So, the formula to find out the mean is:

Mean =

= 150 + (20 Ã— -12/50)

= 150 â€“ 4.8

= 145.20

Thus, mean daily wage of the workers = Rs. 145.20.

### Question 3. The following distribution shows the daily pocket allowance of children of a locality.The mean pocket allowance is Rs 18. Find the missing frequency f.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: Now, we will multiply the classmark with the number of times they have occurred, i.e, with the frequency. As a certain frequency is missing and we have an odd number of class intervals hence, we will assume the middle-Class Mark as our Assumed Mean(A).

Step 3: Now we will apply the general formula to calculate the mean

Now, Let’s see the detailed solution:

The mean formula is

Mean =

= (752 + 20f)/(44 + f)

Now substitute the values and equate to find the missing frequency (f)

â‡’ 18 = (752 + 20f)/(44 + f)

â‡’ 18(44 + f) = (752 + 20f)

â‡’ 792 + 18f = 752 + 20f

â‡’ 792 + 18f = 752 + 20f

â‡’ 792 â€“ 752 = 20f â€“ 18f

â‡’ 40 = 2f

â‡’ f = 20

So, the missing frequency, f = 20.

### Question 4. Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute was recorded and summarized as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: In this case, the value of mid-point (xi) is very large, so let us assume the mean value, A = 75.5 and class size is h = 3.

di = (xi â€“ A)

=> di = (xi â€“ 75.5)

Step 3: Now we will apply the Assumed Mean Formula to calculate the mean

Now, Let’s see the detailed solution:

Mean =

= 75.5 + (12/30)

= 75.5 + 2/5

= 75.5 + 0.4

= 75.9

Therefore, the mean heartbeats per minute for these women is 75.9

### Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?

Solution:

Step 1: In the above table we find that the class intervals are not continuous and hence to make them a continuous set of data we add  0.5 to the upper limit and subtract 0.45 from the lower limit as the gap between two intervals is 1. Then find the Mid Point by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: In this case, let us assume the mean value, A = 57 and class size is h = 3.

Step 3: Since the frequency values are big, hence we are using the STEP-DEVIATION METHOD.

Now, Lets see the detailed solution:

Mean =

= 57 + 3 * (25/400)

= 57 + 0.1875

= 57.19

Therefore, the mean number of mangoes kept in a packing box is 57.19

### Question 6. The table below shows the daily expenditure on the food of 25 households in a locality. Find the mean daily expenditure on food by a suitable method.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: In this case, the value of mid-point (xi) is very large, so let us assume the mean value, A = 225 and class size is h = 50.

di = (xi â€“ A)

=> di = (xi â€“ 225)

ui = (xi â€“ A)/h

=> ui = (xi â€“ 225)/50

Step 3: Now we will apply the Step Deviation Formula to calculate the mean

Now, Let’s see the detailed solution:

Mean =

= 225 + 50 (-7/25)

= 225 – 14

= 211

Therefore, the mean daily expenditure on food is â‚¹211

### Find the mean concentration of SO2 in the air.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: Now, we will multiply the classmark with the number of times they have occurred, i.e, with the frequency.

Step 3: Now we will apply the general formula to calculate the mean

Now, Let’s see the detailed solution:

The formula to find out the mean is

Mean =

= 2.96/30

= 0.099 ppm

Therefore, the mean concentration of SO2 in the air is 0.099 ppm.

### Question 8. A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: Now, we will multiply the classmark with the number of times they have occurred, i.e, with the frequency.

Step 3: Now we will apply the general formula to calculate the mean

Now, Let’s see the detailed solution:

The mean formula is,

Mean =

= 499/40

= 12.48 days

Therefore, the mean number of days a student was absent = 12.48.

### Question 9. The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.

Solution:

Step 1: Let us find out the Class Mark (xi) for the following class intervals by using the formula

Class Mark = (Upper class Limit + Lower Class Limit)/2

Step 2: In this case, the value of mid-point (xi) is very large, so let us assume the mean value, A = 70 and class size is h = 10.

di = (xi â€“ A)

=> di = (xi â€“ 70)

ui = (xi â€“ A)/h

=> ui = (xi â€“ 70)/10

Step 3: Now we will apply the Step Deviation Formula to calculate the mean

Now, Let’s see the detailed solution:

So,

Mean =

= 70 + (-2/35) Ã— 10

= 69.42

Therefore, the mean literacy rate = 69.42%.

My Personal Notes arrow_drop_up
Related Articles