Check if a number has same number of set and unset bits

• Difficulty Level : Easy
• Last Updated : 23 Apr, 2021

Given a number N, the task is to check whether the count of the set and unset bits in the given number are same.
Examples:

Input: 12
Output: Yes
1100 is the binary representation of 12
which has 2 set and 2 unset bits

Input: 14
Output: No

Approach: Traverse in the binary representation of the given number, check if the leftmost bit is set or not using n & 1. If n & 1 returns 1, then the left most bit is set. Right, shift the number every time by 1 to check the next bit. Once the binary representation is traversed completely, check if the number of set bit and unset bits are same. If they are same, print “YES” else print “NO”.
Below is the implementation of the above approach:

C++

 // C++ program to check if a number // has same number of set and unset bits #include using namespace std;   // Function to check if a number // has same setbits and unset bits bool checkSame(int n) {     int set = 0, unset = 0;       // iterate for all bits of a number     while (n) {           // if set         if (n & 1)             set++;         // if unset         else             unset++;           // right shift number by 1         n = n >> 1;     }       // is number of set bits are     // equal to unset bits     if (set == unset)         return true;     else         return false; }   // Driver Code int main() {     int n = 12;       // function to check     if (checkSame(n))         cout << "YES";     else         cout << "NO";     return 0; }

Java

 // Java program to check if // a number has same number // of set and unset bits import java.io.*;   class GFG {       // Function to check if a // number has same setbits // and unset bits static boolean checkSame(int n) {     int set = 0;     int unset = 0;       // iterate for all     // bits of a number     while (n > 0)     {           // if set         if ((n & 1) ==  1)             set++;                       // if unset         else             unset++;           // right shift         // number by 1         n = n >> 1;     }       // is number of set bits     // are equal to unset bits     if (set == unset)         return true;     else         return false; }   // Driver Code public static void main (String[] args) { int n = 12;   // function to check if (checkSame(n))     System.out.println ("YES"); else     System.out.println("NO");       } }   // This code is contributed // by akt_mit

Python3

 # Python program to check if a number # has same number of set and unset bits   # Function to check if a number # has same setbits and unset bits def checkSame(n):     set, unset = 0, 0       # iterate for all bits of a number     while(n):           # if set         if (n and 1):             set + 1                       # if unset         else:             unset += 1           # right shift number by 1         n = n >> 1               # is number of set bits are     # equal to unset bits     if (set == unset):         return True     else:         return False   # Driver Code if __name__ == '__main__':     n = 12       # function to check     if (checkSame(n)):         print("YES")     else:         print("NO")   # This code is contributed # by 29AjayKumar

C#

 // C# program to check if // a number has same number // of set and unset bits using System;   public class GFG{           // Function to check if a // number has same setbits // and unset bits static bool checkSame(int n) {     int set = 0;     int unset = 0;       // iterate for all     // bits of a number     while (n > 0)     {           // if set         if ((n & 1) == 1)             set++;                       // if unset         else             unset++;           // right shift         // number by 1         n = n >> 1;     }       // is number of set bits     // are equal to unset bits     if (set == unset)         return true;     else         return false; }   // Driver Code           static public void Main (){         int n = 12;       // function to check     if (checkSame(n))         Console.WriteLine("YES");     else         Console.WriteLine("NO");           } }

PHP

 > 1;     }       // is number of set bits are     // equal to unset bits     if (\$set == \$unset)         return true;     else         return false; }   // Driver Code \$n = 12;   // function to check if (checkSame(\$n))     echo "YES"; else     echo "NO";   // This code is contributed // by Sach_Code ?>

Javascript



Output:

YES

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