# Check if a number can be expressed as a^b | Set 2

You have given a number n. Check if a number can be represented in the form of pow(a, b) (a^b).

**Examples:**

Input : 4 Output : Yes 2^{2}= 4 Input : 12 Output : No

We have discussed two approaches in Check if a number can be expressed as x^y (x raised to power y). In this post, a more efficient solution is discussed. The idea is based on logarithmic.

Consider a no. N which needs to be expressed in the form (a^b). N = a^{b}Taking log both sides: log (N) = b.log (a) b = log(N)/log(a)

Keep this logic in mind to develop the most efficient solution mentioned below:

## C++

`// CPP program to check if a number` `// can be expressed as a^b.` `#include <bits/stdc++.h>` `using` `namespace` `std;` `bool` `isPower(` `int` `a)` `{` ` ` `if` `(a == 1)` ` ` `return` `true` `;` ` ` `for` `(` `int` `i = 2; i * i <= a; i++) {` ` ` `double` `val = ` `log` `(a) / ` `log` `(i);` ` ` `if` `((val - (` `int` `)val) < 0.00000001)` ` ` `return` `true` `;` ` ` `}` ` ` `return` `false` `;` `}` `// Driver code` `int` `main()` `{` ` ` `int` `n = 16;` ` ` `cout << (isPower(n) ? ` `"Yes"` `: ` `"No"` `);` ` ` `return` `0;` `}` |

## Java

`//Java program to check if a number` `//can be expressed as a^b.` `public` `class` `GFG {` ` ` `static` `boolean` `isPower(` `int` `a)` ` ` `{` ` ` `if` `(a == ` `1` `)` ` ` `return` `true` `;` ` ` `for` `(` `int` `i = ` `2` `; i * i <= a; i++) {` ` ` `double` `val = Math.log(a) / Math.log(i);` ` ` `if` `((val - (` `int` `)val) < ` `0.00000001` `)` ` ` `return` `true` `;` ` ` `}` ` ` `return` `false` `;` ` ` `}` ` ` ` ` `// Driver code` ` ` `public` `static` `void` `main(String[] args) {` ` ` ` ` `int` `n = ` `16` `;` ` ` `System.out.println(isPower(n) ? ` `"Yes"` `: ` `"No"` `);` ` ` `}` `}` |

## Python 3

`# Python 3 Program to check if a number ` `# can be expressed as a^b` `from` `math ` `import` `*` `def` `isPower(a) :` ` ` `if` `a` `=` `=` `1` `:` ` ` `return` `True` ` ` `for` `i ` `in` `range` `(` `2` `, ` `int` `(sqrt(a)) ` `+` `1` `) :` ` ` `val ` `=` `log(a) ` `/` `log(i)` ` ` `if` `(` `round` `((val ` `-` `int` `(val)),` `8` `) < ` `0.00000001` `):` ` ` `return` `True` ` ` ` ` `return` `False` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `n ` `=` `16` ` ` `if` `isPower(n) :` ` ` `print` `(` `"Yes"` `)` ` ` `else` `:` ` ` `print` `(` `"No"` `)` `# This code is contributed by ANKITRAI1` |

## C#

`// C# program to check if a number ` `// can be expressed as a^b. ` `using` `System;` `class` `GFG` `{` `public` `static` `bool` `isPower(` `int` `a)` `{` ` ` `if` `(a == 1)` ` ` `{` ` ` `return` `true` `;` ` ` `}` ` ` `for` `(` `int` `i = 2; i * i <= a; i++)` ` ` `{` ` ` `double` `val = Math.Log(a) / ` ` ` `Math.Log(i);` ` ` `if` `((val - (` `int` `)val) < 0.00000001)` ` ` `{` ` ` `return` `true` `;` ` ` `}` ` ` `}` `return` `false` `;` `}` `// Driver code ` `public` `static` `void` `Main(` `string` `[] args)` `{` ` ` `int` `n = 16;` ` ` `Console.WriteLine(isPower(n) ? ` ` ` `"Yes"` `: ` `"No"` `);` `}` `}` `// This code is contributed ` `// by Shrikant13` |

## PHP

`<?php` `// PHP program to check if a number` `// can be expressed as a^b.` `function` `isPower(` `$a` `)` `{` ` ` `if` `(` `$a` `== 1)` ` ` `return` `true;` ` ` `for` `(` `$i` `= 2; ` `$i` `* ` `$i` `<= ` `$a` `; ` `$i` `++)` ` ` `{` ` ` `$val` `= log(` `$a` `) / log(` `$i` `);` ` ` `if` `((` `$val` `- ` `$val` `) < 0.00000001)` ` ` `return` `true;` ` ` `}` ` ` `return` `false;` `}` `// Driver code` `$n` `= 16;` `echo` `(isPower(` `$n` `) ? ` `"Yes"` `: ` `"No"` `);` `// This code is contributed ` `// by Akanksha Rai(Abby_akku)` |

## Javascript

`<script>` `//Javascript program to check if a number` `//can be expressed as a^b.` ` ` ` ` `function` `isPower(a)` ` ` `{` ` ` `if` `(a == 1)` ` ` `return` `true` `;` ` ` ` ` `for` `(let i = 2; i * i <= a; i++) {` ` ` `let val = Math.log(a) / Math.log(i);` ` ` `if` `((val - Math.floor(val)) < 0.00000001)` ` ` `return` `true` `;` ` ` ` ` `}` ` ` ` ` `return` `false` `;` ` ` ` ` `}` ` ` ` ` `// Driver code` ` ` `let n = 16;` ` ` `document.write(isPower(n) ? ` `"Yes"` `: ` `"No"` `);` ` ` ` ` ` ` `// This code is contributed by avanitrachhadiya2155` `</script>` |

**Output**

Yes

**Time Complexity : **O(sqrt(n))