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# Check if both halves of the string have same set of characters in Python

• Difficulty Level : Easy
• Last Updated : 27 Jul, 2022

Given a string of lowercase characters only, the task is to check if it is possible to split a string from middle which will gives two halves having the same characters and same frequency of each character. If the length of the given string is ODD then ignore the middle element and check for the rest. Examples:

```Input : abbaab
Output : NO
The two halves contain the same characters
but their frequencies do not match so they
are NOT CORRECT

Input : abccab
Output : YES```

This problem has existing solution, please refer Check if both halves of the string have same set of characters link. We will solve this problem in Python quickly using Dictionary comparison. Approach is very simple :

1. Break string in two parts and convert both parts into dictionary using Counter(iterator) method, each dictionary contains it’s character as key and frequency as value.
2. Now compare these two dictionaries. In python we can compare two using == operator, it first checks keys of both dictionaries are same or not, then it checks for values of each key. If everything is equal that means two dictionaries are identical.

Implementation:

## Python3

 `# Function to Check if both halves of ` `# the string have same set of characters ` `from` `collections ``import` `Counter `   `def` `checkTwoHalves(``input``): ` `    `  `    ``length ``=` `len``(``input``) ` `    `  `    ``# Break input string in two parts ` `    ``if` `(length ``%` `2` `!``=` `0``): ` `        ``first ``=` `input``[``0``:length ``/``/` `2``] ` `        ``second ``=` `input``[(length ``/``/` `2``) ``+` `1``:] ` `    ``else``: ` `        ``first ``=` `input``[``0``:length ``/``/` `2``] ` `        ``second ``=` `input``[length ``/``/` `2``:] `   `    ``# Convert both halves into dictionary and compare ` `    ``if` `Counter(first) ``=``=` `Counter(second): ` `        ``print` `(``'YES'``)` `    ``else``: ` `        ``print` `(``'NO'``)`   `# Driver program ` `if` `__name__ ``=``=` `"__main__"``: ` `    ``input` `=` `'abbaab'` `    ``checkTwoHalves(``input``) `

Output

`NO`

Time Complexity: O(n)
Auxiliary Space: O(n)

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