# C Program To Check Leap Year

• Last Updated : 19 Jul, 2022

A year is a leap year if the following conditions are satisfied:

1. The year is multiple of 400.
2. The year is multiple of 4 and not multiple of 100.

Following is pseudo-code

```if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year```

## C

 `// C program to check if a given ` `// year is leap year or not` `#include ` `#include `   `bool` `checkYear(``int` `year)` `{` `    ``// If a year is multiple of 400, ` `    ``// then it is a leap year` `    ``if` `(year % 400 == 0)` `        ``return` `true``;`   `    ``// Else If a year is multiple of 100,` `    ``// then it is not a leap year` `    ``if` `(year % 100 == 0)` `        ``return` `false``;`   `    ``// Else If a year is multiple of 4,` `    ``// then it is a leap year` `    ``if` `(year % 4 == 0)` `        ``return` `true``;` `    ``return` `false``;` `}`   `// Driver code` `int` `main()` `{` `    ``int` `year = 2000;`   `    ``checkYear(year)? ``printf``(``"Leap Year"``):` `                     ``printf``(``"Not a Leap Year"``);` `    ``return` `0;` `}`

Output:

`Leap Year`

Time Complexity: O(1)

Auxiliary Space: O(1)

How to write the above code in one line?

## C

 `// One line C program to check if a ` `// given year is leap year or not` `#include ` `#include `   `bool` `checkYear(``int` `year)` `{` `// Return true if year is a multiple` `// of 4 and not multiple of 100.` `// OR year is multiple of 400.` `return` `(((year % 4 == 0) && ` `        ``(year % 100 != 0)) ||` `        ``(year % 400 == 0));` `}`   `// Driver code` `int` `main()` `{` `    ``int` `year = 2000;`   `    ``checkYear(year)? ``printf``(``"Leap Year"``):` `                     ``printf``(``"Not a Leap Year"``);` `    ``return` `0;` `}`

Output:

`Leap Year`

Time Complexity: O(1)

Auxiliary Space: O(1)

Please refer complete article on Program to check if a given year is leap year for more details!

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