C | Pointer Basics | Question 13

int f(int x, int *py, int **ppz)
{
  int y, z;
  **ppz += 1;
   z  = **ppz;
  *py += 2;
   y = *py;
   x += 3;
   return x + y + z;
}

void main()
{
   int c, *b, **a;
   c = 4;
   b = &c;
   a = &b;
   printf("%d ", f(c, b, a));
   return 0;
}

(A) 18
(B) 19
(C) 21
(D) 22


Answer: (B)

Explanation: Let us understand this line by line

  /* below line changes value of c to 5. Note that x remains unaffected by 
    this change as x is a copy of c and address of x is different from c*/
  **ppz += 1  
  
  /* z is changed to 5*/
  z  = **ppz; 
  
  /* changes c to 7, x is not changed */
  *py += 2; 
  
   /* y is changed to 7*/
  y = *py;    
  
  /* x is incremented by 3 */
   x += 3;    
  
  /* return 7 + 7 + 5*/
  return x + y + z;

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