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C | Arrays | Question 3

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  • Difficulty Level : Medium
  • Last Updated : 14 Mar, 2019
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What is output?




# include <stdio.h>
  
void print(int arr[])
{
   int n = sizeof(arr)/sizeof(arr[0]);
   int i;
   for (i = 0; i < n; i++)
      printf("%d ", arr[i]);
}
  
int main()
{
   int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
   print(arr);
   return 0;
}


(A) 1, 2, 3, 4, 5, 6, 7, 8
(B) Compiler Error
(C) 1 2
(D) Run Time Error


Answer: (C)

Explanation: See https://www.geeksforgeeks.org/using-sizof-operator-with-array-paratmeters/ for explanation.

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