BFS using vectors & queue as per the algorithm of CLRS
Breadth-first search traversal of a graph using the algorithm given in CLRS book.
BFS is one of the ways to traverse a graph. It is named so because it expands the frontier between discovered and undiscovered vertices uniformly across the breadth of the frontier. What it means is that the algorithm first discovers all the vertices connected to “u” at a distance of k before discovering the vertices at a distance of k+1 from u. The algorithm given in CLRS uses the concept of “colour” to check if a vertex is discovered fully or partially or undiscovered. It also keeps a track of the distance a vertex u is from the source s.
BFS(G,s) 1 for each vertex u in G.V - {s} 2 u.color = white 3 u.d = INF 4 u.p = NIL 5 s.color = green 6 s.d = 0 7 s.p = NIL 8 Q = NULL 9 ENQUEUE(Q,s) 10 while Q != NULL 11 u = DEQUEUE(Q) 12 for each v in G.Adj[u] 13 if v.color == white 14 v.color = green 15 v.d = u.d + 1 16 v.p = u 17 ENQUEUE(Q,v) 18 u.color = dark_green
It produces a “breadth-first tree” with root s that contains all reachable vertices. Let’s take a simple directed graph and see how BFS traverses it.

The graph

Starting of traversal

1st traversal

1st traversal completes
Implementation:
C++
// CPP program to implement BFS as per CLRS // algorithm. #include <bits/stdc++.h> using namespace std; // Declaring the vectors to store color, distance // and parent vector<string> colour; vector< int > d; vector< int > p; /* This function adds an edge to the graph. It is an undirected graph. So edges are added for both the nodes. */ void addEdge(vector < int > g[], int u, int v) { g[u].push_back(v); g[v].push_back(u); } /* This function does the Breadth First Search*/ void BFSSingleSource(vector < int > g[], int s) { // The Queue used for the BFS operation queue< int > q; // Pushing the root node inside the queue q.push(s); /* Distance of root node is 0 & colour is gray as it is visited partially now */ d[s] = 0; colour[s] = "green" ; /* Loop to traverse the graph. Traversal will happen traverse until the queue is not empty.*/ while (!q.empty()) { /* Extracting the front element(node) and popping it out of queue. */ int u = q.front(); q.pop(); cout << u << " " ; /* This loop traverses all the child nodes of u */ for ( auto i = g[u].begin(); i != g[u].end(); i++) { /* If the colour is white then the said node is not traversed. */ if (colour[*i] == "white" ) { colour[*i] = "green" ; d[*i] = d[u] + 1; p[*i] = u; /* Pushing the node inside queue to traverse its children. */ q.push(*i); } } /* Now the node u is completely traversed and colour is changed to black. */ colour[u] = "dark_green" ; } } void BFSFull(vector < int > g[], int n) { /* Initially all nodes are not traversed. Therefore, the colour is white. */ colour.assign(n, "white" ); d.assign(n, 0); p.assign(n, -1); // Calling BFSSingleSource() for all white // vertices. for ( int i = 0; i < n; i++) if (colour[i] == "white" ) BFSSingleSource(g, i); } // Driver Function int main() { // Graph with 7 nodes and 6 edges. int n = 7; // The Graph vector vector < int > g[n]; addEdge(g, 0, 1); addEdge(g, 0, 2); addEdge(g, 1, 3); addEdge(g, 1, 4); addEdge(g, 2, 5); addEdge(g, 2, 6); BFSFull(g, n); return 0; } |
Java
// Java program to implement BFS as per CLRS // algorithm. import java.io.*; import java.util.*; public class Graph { private int V; private LinkedList<Integer>[] g; // Declaring the arrays to store color, distance // and parent String[] colour; int [] d, p; // Constructor @SuppressWarnings ( "unchecked" ) Graph( int v) { V = v; g = new LinkedList[v]; for ( int i = 0 ; i < v; i++) g[i] = new LinkedList<Integer>(); } // Function to add an edge into the graph void addEdge( int u, int v) { g[u].add(v); g[v].add(u); } // This function does the Breadth First Search void BFSSingleSource( int s) { // The Queue used for the BFS operation Queue<Integer> q = new LinkedList<>(); // Pushing the root node inside the queue q.add(s); /* Distance of root node is 0 & colour is gray as it is visited partially now */ d[s] = 0 ; colour[s] = "green" ; /* Loop to traverse the graph. Traversal will happen traverse until the queue is not empty.*/ while (!q.isEmpty()) { /* Extracting the front element(node) and popping it out of queue. */ int u = q.poll(); System.out.print(u + " " ); /* This loop traverses all the child nodes of u */ for ( int i : g[u]) { /* If the colour is white then the said node is not traversed. */ if (colour[i] == "white" ) { colour[i] = "green" ; d[i] = d[u] + 1 ; p[i] = u; /* Pushing the node inside queue to traverse its children. */ q.add(i); } } /* Now the node u is completely traversed and colour is changed to black. */ colour[u] = "dark_green" ; } System.out.println(); } void BFSFull( int n) { /* Initially all nodes are not traversed. Therefore, the colour is white. */ colour = new String[n]; d = new int [n]; p = new int [n]; Arrays.fill(colour, "white" ); Arrays.fill(d, 0 ); Arrays.fill(p, - 1 ); // Calling BFSSingleSource() for all white // vertices. for ( int i = 0 ; i < n; i++) { if (colour[i] == "white" ) BFSSingleSource(i); } } // Driver method public static void main(String[] args) { int n = 7 ; Graph g = new Graph(n); g.addEdge( 0 , 1 ); g.addEdge( 0 , 2 ); g.addEdge( 1 , 3 ); g.addEdge( 1 , 4 ); g.addEdge( 2 , 5 ); g.addEdge( 2 , 6 ); g.BFSFull(n); } } // This code is contributed by cavi4762. |
Python3
# Python3 program to implement BFS as # per CLRS algorithm. import queue # This function adds an edge to the graph. # It is an undirected graph. So edges # are added for both the nodes. def addEdge(g, u, v): g[u].append(v) g[v].append(u) # This function does the Breadth # First Search def BFSSingleSource(g, s): # The Queue used for the BFS operation q = queue.Queue() # Pushing the root node inside # the queue q.put(s) # Distance of root node is 0 & colour is # gray as it is visited partially now d[s] = 0 colour[s] = "green" # Loop to traverse the graph. Traversal # will happen traverse until the queue # is not empty. while ( not q.empty()): # Extracting the front element(node) # and popping it out of queue. u = q.get() print (u, end = " " ) # This loop traverses all the child # nodes of u i = 0 while i < len (g[u]): # If the colour is white then # the said node is not traversed. if (colour[g[u][i]] = = "white" ): colour[g[u][i]] = "green" d[g[u][i]] = d[u] + 1 p[g[u][i]] = u # Pushing the node inside queue # to traverse its children. q.put(g[u][i]) i + = 1 # Now the node u is completely traversed # and colour is changed to black. colour[u] = "dark_green" def BFSFull(g, n): # Initially all nodes are not traversed. # Therefore, the colour is white. colour = [ "white" ] * n d = [ 0 ] * n p = [ - 1 ] * n # Calling BFSSingleSource() for all # white vertices for i in range (n): if (colour[i] = = "white" ): BFSSingleSource(g, i) # Driver Code # Graph with 7 nodes and 6 edges. n = 7 # Declaring the vectors to store color, # distance and parent colour = [ None ] * n d = [ None ] * n p = [ None ] * n # The Graph vector g = [[] for i in range (n)] addEdge(g, 0 , 1 ) addEdge(g, 0 , 2 ) addEdge(g, 1 , 3 ) addEdge(g, 1 , 4 ) addEdge(g, 2 , 5 ) addEdge(g, 2 , 6 ) BFSFull(g, n) # This code is contributed by Pranchalk |
C#
using System; using System.Collections.Generic; namespace GraphTraversal { public class Graph { private int V; private List< int >[] g; // Declaring the arrays to store color, distance // and parent string [] colour; int [] d, p; // Constructor Graph( int v) { V = v; g = new List< int >[ v ]; for ( int i = 0; i < v; i++) g[i] = new List< int >(); } // Function to add an edge into the graph void addEdge( int u, int v) { g[u].Add(v); g[v].Add(u); } // This function does the Breadth First Search void BFSSingleSource( int s) { // The Queue used for the BFS operation Queue< int > q = new Queue< int >(); // Pushing the root node inside the queue q.Enqueue(s); /* Distance of root node is 0 & colour is gray as it is visited partially now */ d[s] = 0; colour[s] = "green" ; /* Loop to traverse the graph. Traversal will happen traverse until the queue is not empty.*/ while (q.Count != 0) { /* Extracting the front element(node) and popping it out of queue. */ int u = q.Dequeue(); Console.Write(u + " " ); /* This loop traverses all the child nodes of u */ foreach ( int i in g[u]) { /* If the colour is white then the said node is not traversed. */ if (colour[i] == "white" ) { colour[i] = "green" ; d[i] = d[u] + 1; p[i] = u; /* Pushing the node inside queue to traverse its children. */ q.Enqueue(i); } } /* Now the node u is completely traversed and colour is changed to black. */ colour[u] = "dark_green" ; } Console.WriteLine(); } void BFSFull( int n) { /* Initially all nodes are not traversed. Therefore, the colour is white. */ colour = new string [n]; d = new int [n]; p = new int [n]; Array.Fill(colour, "white" ); Array.Fill(d, 0); Array.Fill(p, -1); // Calling BFSSingleSource() for all white // vertices. for ( int i = 0; i < n; i++) { if (colour[i] == "white" ) BFSSingleSource(i); } } // Driver method static void Main( string [] args) { int n = 7; Graph g = new Graph(7); g.addEdge(0, 1); g.addEdge(0, 2); g.addEdge(1, 3); g.addEdge(1, 4); g.addEdge(2, 5); g.addEdge(2, 6); g.BFSFull(n); } } } // This code is contributed by ishankhandelwals. |
Javascript
<script> // Javascript program to implement BFS as per CLRS // algorithm. // Declaring the vectors to store color, distance // and parent var colour = []; var d = []; var p = []; /* This function adds an edge to the graph. It is an undirected graph. So edges are added for both the nodes. */ function addEdge(g, u, v) { g[u].push(v); g[v].push(u); } /* This function does the Breadth First Search*/ function BFSSingleSource(g, s) { // The Queue used for the BFS operation var q = []; // Pushing the root node inside the queue q.push(s); /* Distance of root node is 0 & colour is gray as it is visited partially now */ d[s] = 0; colour[s] = "green" ; /* Loop to traverse the graph. Traversal will happen traverse until the queue is not empty.*/ while (q.length!=0) { /* Extracting the front element(node) and popping it out of queue. */ var u = q[0]; q.shift(); document.write( u + " " ); /* This loop traverses all the child nodes of u */ for ( var i of g[u]) { /* If the colour is white then the said node is not traversed. */ if (colour[i] == "white" ) { colour[i] = "green" ; d[i] = d[u] + 1; p[i] = u; /* Pushing the node inside queue to traverse its children. */ q.push(i); } } /* Now the node u is completely traversed and colour is changed to black. */ colour[u] = "dark_green" ; } } function BFSFull(g, n) { /* Initially all nodes are not traversed. Therefore, the colour is white. */ colour = Array(n).fill( "white" ); d = Array(n).fill(0); p = Array(n).fill(0); // Calling BFSSingleSource() for all white // vertices. for ( var i = 0; i < n; i++) if (colour[i] == "white" ) BFSSingleSource(g, i); } // Driver Function // Graph with 7 nodes and 6 edges. var n = 7; // The Graph vector var g = Array.from(Array(n), ()=>Array()); addEdge(g, 0, 1); addEdge(g, 0, 2); addEdge(g, 1, 3); addEdge(g, 1, 4); addEdge(g, 2, 5); addEdge(g, 2, 6); BFSFull(g, n); // This code is contributed by rutvik_56. </script> |
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Time Complexity: O(V+E) – we traverse all vertices at least once and check every edge.
Auxiliary Space: O(V) – for using a queue to store vertices.
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