8085 program to convert an 8 bit number into Grey number

Prerequisite – Binary to/from Gray Code
Problem – Write an assembly language program in 8085 which convert an 8 bit number into grey number

Example –

Assumption – 8 bit number (input) is stored at memory location 2050 and output to be stored at memory location 3050.

Algorithm –

1. Load the content of memory location 2050 in Accumulator
2. Reset carry flag i.e. CY = 0
3. Rotate the contents of Accumulator right by 1 bit with carry and perform xor operation with initial value of input
4. Store the result at memory location 3050

Program –

MEMORY ADDRESS	MNEMONICS	COMMENT
2000	LDA 2050	A <- M[2050]
2003	MOV B, A	B <- A
2004	STC	CY = 1
2005	CMC	CY <- complement of CY
2006	RAR	Rotate 1 bit right with carry
2007	XRA B	A <- A XOR B
2008	STA 3050	M[3050] <- A
200B	HLT	End of program

Explanation –

1. LDA 2050 loads the content of memory location 2050 in accumulator
2. MOV B, A transfers the content of register A in register B
3. STC sets the carry flag i.e. CY becomes 1
4. CMC complements the carry flag i.e. CY becomes 0
5. RAR rotate the content of accumulator by 1 bit along with carry flag
6. XRA B performs the xor operation in values of register A and register B and store the result in A
7. STA 3050 stores the value of accumulator in memory location 3050
8. HLT stops executing the program and halts any further execution

My Personal Notes arrow_drop_up

Save