Aptitude | Trigonometry & Height and Distances | Question 5

The least value of 2sin²θ + 3cos²θ
(A) 1/3
(B) 4/3
(C) 2
(D) 3/4


Answer: (C)

Explanation: = 2sin²θ + 2cos²θ + cos²θ

=2(sin²θ + cos²θ) + cos²θ ; (by putting sin²θ + cos²=1)

= 2 + cos²θ ;(the minimum value of cos²θ=0)

= 2 + 0 = 2

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