Aptitude | Progressions | Question 8

Find the sum of series: 1/3, 1/9, 1/27, 1/81……………..
(A) 1/2
(B) 1/3
(C) 1/4
(D) 1/6


Answer: (A)

Explanation:

The given series is an infinite GP, whose sum is given by Sn=a/(r-1)
Where,
a=first term of series,
r=common ratio.

Therefore,

Sn=(1/3)/(1-1/3)
Sn=1/2

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