If ab bc ac 0 then the value of TEX frac 1 a 2 bc frac 1 b 2 ac frac 1 c 2 ab TEX

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Aptitude | Algebra | Question 9

Last Updated : 28 Jun, 2021

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If ab+bc+ac = 0, then the value of $\frac{1}{a^{2}-bc} + \frac{1}{b^{2}-ac} + \frac{1}{c^{2}-ab}$
(A) 6
(B) 2
(C) 3
(D) 0

Answer: (D)

Explanation: Put -ac = ab + bc ; -ab = ac+ bc and -bc =ab + ac

(ab + bc + ca)/[(a+b+c)(abc)]

as, ab+bc+ca=0

= 0

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